Answer:
Time taken to travel from one track to the next = 0.08ms
Initial track= 15 0
4 (15-4)*(0.08)= 0.88
40 (40-4)*(0.08)= 2.88
35 (40-35)*(0.08)= 0.4
11 (35-11)*(0.08)= 1.92
14 (14-11)*(0.08)= 0.24
7 (14-7)*(0.08)= 0.56
----------------------------------------------
Total seek time=0.88+2.88+0.4+1.92+0.24+0.56=6.88ms
Explanation:
We caculate the seek time for each request, and then add them together to find the total seek time. The final track number for the current request becomes the current track of next request, and this process is repeated till the last request is processed.
Answer:
To an official government website containing information relating to tours and events of the White House.
Explanation:
Hope this helps! :D
Answer: D
Local news channels
Explanation:
Since Jack is trying to improve local service the local news would be the best fit to reach the maximum amount of people in his area.
Answer:
The given statement is false statement.
Explanation .
- The assignment is assigning the value to the variable or we can say that it will also be used to initialize the variable The "=" is the symbol of the assignment operator.
int r=90, The value of variable 90 is assigned to 90.
- The associativity, of assignment, is always right to left which means The right-hand side is firstly evaluated then it will be assigned in left-hand side variable or expression.
Answer:
LA15; LA22
LA16; LA31; LA32
LA169; LA126;
LA127; LA141
Explanation:
Given

Required
Course sequence to satisfy the prerequisite
From the course prerequisite, we have:
and 
This means that LA15 and LA22 are the base courses, and they have no prerequisite. So, we have:
![[LA15; LA22]](https://tex.z-dn.net/?f=%5BLA15%3B%20LA22%5D)
LA16 and LA31 have LA15 as their direct course prerequisite. So, the sequence becomes
![[LA15 \to [LA16, LA31]; LA22]](https://tex.z-dn.net/?f=%5BLA15%20%5Cto%20%5BLA16%2C%20LA31%5D%3B%20LA22%5D)
To complete the sequence, we read each course and place them other their prerequisite.
<em>See attachment for complete tree</em>
<em></em>
From the tree, we have the sequence to be:
<em>LA15; LA22</em>
<em>LA16; LA31; LA32</em>
<em>LA169; LA126;</em>
<em>LA127; LA141</em>
<em />