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adoni [48]
3 years ago
9

The sum or two numbers are 25 their differences is 7 find the two numbers

Mathematics
1 answer:
andrey2020 [161]3 years ago
6 0
Set up a system of equations:
x+y=25
x-y=7

Use the cancellation method (that's what I call it):
Add the x's together, the y's together, and the constants together to make one big mashed up equation you can solve.

2x=32
x=16

Substitute the number back in to the equation:
x+y=25
16+y=25
y=9

The numbers are 16 and 9. Sorry for the long answer!
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Room temperature ranges from 20°C to 25°C. Find the range of room temperature in °F. Use the formula F – 32 = 1.8C to convert fr
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Answer:

68 to 77

Step-by-step explanation:

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5 0
3 years ago
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For the function defined by f(t)=2-t, 0≤t<1, sketch 3 periods and find:
Oksi-84 [34.3K]
The half-range sine series is the expansion for f(t) with the assumption that f(t) is considered to be an odd function over its full range, -1. So for (a), you're essentially finding the full range expansion of the function

f(t)=\begin{cases}2-t&\text{for }0\le t

with period 2 so that f(t)=f(t+2n) for |t| and integers n.

Now, since f(t) is odd, there is no cosine series (you find the cosine series coefficients would vanish), leaving you with

f(t)=\displaystyle\sum_{n\ge1}b_n\sin\frac{n\pi t}L

where

b_n=\displaystyle\frac2L\int_0^Lf(t)\sin\frac{n\pi t}L\,\mathrm dt

In this case, L=1, so

b_n=\displaystyle2\int_0^1(2-t)\sin n\pi t\,\mathrm dt
b_n=\dfrac4{n\pi}-\dfrac{2\cos n\pi}{n\pi}-\dfrac{2\sin n\pi}{n^2\pi^2}
b_n=\dfrac{4-2(-1)^n}{n\pi}

The half-range sine series expansion for f(t) is then

f(t)\sim\displaystyle\sum_{n\ge1}\frac{4-2(-1)^n}{n\pi}\sin n\pi t

which can be further simplified by considering the even/odd cases of n, but there's no need for that here.

The half-range cosine series is computed similarly, this time assuming f(t) is even/symmetric across its full range. In other words, you are finding the full range series expansion for

f(t)=\begin{cases}2-t&\text{for }0\le t

Now the sine series expansion vanishes, leaving you with

f(t)\sim\dfrac{a_0}2+\displaystyle\sum_{n\ge1}a_n\cos\frac{n\pi t}L

where

a_n=\displaystyle\frac2L\int_0^Lf(t)\cos\frac{n\pi t}L\,\mathrm dt

for n\ge0. Again, L=1. You should find that

a_0=\displaystyle2\int_0^1(2-t)\,\mathrm dt=3

a_n=\displaystyle2\int_0^1(2-t)\cos n\pi t\,\mathrm dt
a_n=\dfrac2{n^2\pi^2}-\dfrac{2\cos n\pi}{n^2\pi^2}+\dfrac{2\sin n\pi}{n\pi}
a_n=\dfrac{2-2(-1)^n}{n^2\pi^2}

Here, splitting into even/odd cases actually reduces this further. Notice that when n is even, the expression above simplifies to

a_{n=2k}=\dfrac{2-2(-1)^{2k}}{(2k)^2\pi^2}=0

while for odd n, you have

a_{n=2k-1}=\dfrac{2-2(-1)^{2k-1}}{(2k-1)^2\pi^2}=\dfrac4{(2k-1)^2\pi^2}

So the half-range cosine series expansion would be

f(t)\sim\dfrac32+\displaystyle\sum_{n\ge1}a_n\cos n\pi t
f(t)\sim\dfrac32+\displaystyle\sum_{k\ge1}a_{2k-1}\cos(2k-1)\pi t
f(t)\sim\dfrac32+\displaystyle\sum_{k\ge1}\frac4{(2k-1)^2\pi^2}\cos(2k-1)\pi t

Attached are plots of the first few terms of each series overlaid onto plots of f(t). In the half-range sine series (right), I use n=10 terms, and in the half-range cosine series (left), I use k=2 or n=2(2)-1=3 terms. (It's a bit more difficult to distinguish f(t) from the latter because the cosine series converges so much faster.)

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4 years ago
How much candy can a human being fit in their mouth?
7nadin3 [17]
I don’t know but a better question is how many cavities do that human being want since they’re tryna see how much candy they can put in their mouth ? :)
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3 years ago
Part1; The nth term of a geometric sequence is given by a_n = 4(0.75)^n-1, write the first five terms, and find the 5th partial
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Just take n=1,2,3,4,5 respectively to find out the first 5 terms.

First 5 terms = 4,3,2.25,1.69 respectively.

For the 5th partial sum, just add the first 5 terms.

5th partial sum = 10.34

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First 4 terms : 5,8,11,14 respectively.

Now you need to find the other next 4 terms to find out the 8th partial sum.

17,20,23,26

8th partial sum = 124

Hope this helps:)
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3 years ago
It says find the perimeter of the figure below.
PtichkaEL [24]
I think it’s 37 inches
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3 years ago
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