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1 year ago

How much momentum does a 50 kg mass moving west at 10 m/s have?

Mathematics

1 answer:

musickatia [10]1 year ago

3 0

Answer:

(a) 500 kg·m/s west

Step-by-step explanation:

Momentum is the product of mass and velocity.

p = mv

p = (50 kg)(10 m/2 west)

p = 500 kg·m/s west

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Mr. Joseph bought 9 pounds of fertilizer for his lawn. He uses 2 2/3 pounds for his backyard and 1 2/9 for his front yard. How m

arlik [135]

2 2/3 + 1 2/9 = 3.7 9 - 3.7 = 5.3 so the answer would be 5.3 pounds of fertilizer left. Hope this helps!

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2 years ago

Suppose that on each play of a game, a gambler either wins 1 with probability p or loses 1 with probability 1–p (or q). The gamb

musickatia [10]

Answer:

Step-by-step explanation:

From the given information,

Considering both cases when p = 0.5 and when p ≠ 0.5

the probability that the gambler will quit an overall winner is:

$P = \dfrac{1 - (\dfrac{1-p}{p} )^K}{1- (\dfrac{1-p}{p})^N } \ \ \ is \ p \neq 0.5 \ and\ K/N = \dfrac{1}{2}$

where ;

N.k = n and k = m

Hence, the probability changes to:

$P = \dfrac{1 -(\dfrac{1-p}{p})^m}{1 -(\dfrac{1-p}{p})^{m+n}}$ is p ≠ 0.5 and k/N = $\dfrac{m}{m+n}$ is P = 0.5

3 0

2 years ago

(ASAPPP) The position of an object at time t is given by s(t) = -2 - 6t. Find the instantaneous velocity at t = 2 by finding the

prohojiy [21]

Answer:

The instantaneous velocity at $t = 2$ is $-6$ .

Step-by-step explanation:

We have the position as the function

$s(t) = -2 - 6t$

As we know that the velocity is the rate of change of position over time, so it is basically the derivative of the function.

so finding the derivate of $s(t) = -2 - 6t$

∴ $s'(t)=-6$

The instantaneous velocity at $t = 2$

$s'(2)=-6$

Therefore, the instantaneous velocity at $t = 2$ is $-6$ .

Please note that the negative value indicates the direction of movement, in this case, it would be backward.

7 0

2 years ago

Someone plz help me :(

jeka94

Answer:

Step-by-step explanation:

7 0

2 years ago

Carly's family traveled 3/10 of the distance to her grandmother's house on Saturday. They traveled 3/7 of the remaining distance

polet [3.4K]

Answer:

3/10 of the total distance to her grandmother's house was traveled on Sunday

Step-by-step explanation:

Carly's family traveled distance of Saturday = $\frac{3}{10}$

Remaining distance = $1-\frac{3}{10}=\frac{7}{10}$

They traveled 3/7 of the remaining distance on Sunday.

So, Distance traveled on Sunday = $\frac{3}{7}(\frac{7}{10})$

Distance traveled on Sunday = $\frac{3}{10}$

Fraction of the total distance to her grandmother's house was traveled on Sunday = $\frac{3}{10}$

Hence 3/10 of the total distance to her grandmother's house was traveled on Sunday

5 0

2 years ago