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svet-max [94.6K]
3 years ago
9

A prime number less than 100 is selected randomly. what is the probability that its square has units digit $7$?

Mathematics
1 answer:
liberstina [14]3 years ago
4 0
Any number ends with 0, 1, 2, 3, 4, 5, 6, 7, 8 or  9

Given any number. The square of this number is the last digit of square of the original numbers units digit.

For example

23*23 ends with 9 (3*3=9)

149*149 ends with 1 (9*9=81)

2564*2564 ends with 6 (4*4=16) 

and so on

so all the possible unit digits of a square number are {0, 1, 4, 5, 6, 9}

because:

0*0= 0 ; 1*1=1; 2*2=4; 3*3=9; 4*4=16; 5*5=25, 6*6=36; 7*7=49; 8*8=64, 9*9=81

Thus, the probability that the square of a number selected from any set of numbers being 7, is 0.


Answer: 0
 

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What is the solution to the equation 6n+7=55
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Answer:

n = 8

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

Step-by-step explanation:

<u>Step 1: Define Equation</u>

6n + 7 = 55

<u>Step 2: Solve for </u><em><u>n</u></em>

  1. Subtract 7 on both sides:                    6n = 48
  2. Divide 6 on both sides:                       n = 8

<u>Step 3: Check</u>

<em>Plug in n into the original equation to verify it's a solution.</em>

  1. Substitute in <em>n</em>:                    6(8) + 7 = 55
  2. Multiply:                               48 + 7 = 55
  3. Add:                                     55 = 55

Here we see that 55 does indeed equal 55.

∴ n = 8 is a solution of the equation.

7 0
3 years ago
Read 2 more answers
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