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larisa86 [58]
3 years ago
5

What is the x and y intercept

Mathematics
1 answer:
Olenka [21]3 years ago
5 0
Look carefully at the point where the 2 lines intersect.  From that point, look straight down to the x-axis; you'll see that the x-value there is 50.  Similarly,
starting at the intersection, look straight left to the y-axis; the y-value there is 11.

Thus, the coordinates of the intersection (i. e., the solution) are found in (50,11).
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What is the area of the above trapezoid? Please help<br> I will cash app if you help out
Leno4ka [110]

Answer:

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Step-by-step explanation:

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2/5 ÷ -2/5 plzz answer 20 points​
Olegator [25]

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-0.04

Step-by-step explanation:

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2 years ago
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8) A pyramid has a rectangluar base with length 12 km and width of 5 km. If the volume is 200
SashulF [63]

Hi there!

\large\boxed{h = 10km}

We know that the equation for the volume of a pyramid is:

V = 1/3(bh)

We know that:

V = 200 km³

b = 12 × 5 = 60 km²

We can plug these into the equation:

200 = 1/3(60)(h)

Simplify:

200 = 20h

Divide both sides by 20:

200/20 = 20h/20

h = 10 km

6 0
3 years ago
Plant A: A graph has time (weeks) on the x-axis, and height (inches) on the y-axis. A line goes through points (0, 3), (1, 4.8),
butalik [34]

Answer:

The correct option is;

No, The greater rate of change of Plant A will result in it being 0.9 inches taller in 6 weeks

Step-by-step explanation:

The parameters given are;

Plant A:

Weeks,    Height

0,               3

1,                4.8

2,               6.6

3,               8.4

The rate of change of height, H per week, t,\left (\dfrac{dH}{dt} \right )  for plant A per week is therefore;

\dfrac{dH}{dt} =  \dfrac{H_n - H_{(n-1)} }{t_n - t_{(n-1)}} = \dfrac{8.4 - 3 }{3 - 0} = \dfrac{5.4}{3} = 1.8 \ inches/week

Therefore we have;

H = 1.8 × t + 3

At week 6,

H = 3 + 6×1.8 = 13.8 inches

Plant B

Weeks,    Height

2,               7.3

3,               8.7

4,               10.1

The rate of change of height, H per week, t,\left (\dfrac{dH}{dt} \right )  for plant B per week is given as follows;

\dfrac{dH}{dt} =  \dfrac{H_n - H_{(n-1)} }{t_n - t_{(n-1)}} = \dfrac{10.1 - 7.3 }{4 - 2} = \dfrac{2.8}{2} = 1.4 \ inches/week

Therefore we have;

When t = 2, H = 7.3 hence, 7.3 = 2 × 1.4 + H₀

Where:

H₀ = H at t = 0

H₀ = 7.3 - 2 × 1.4 = 4.5

At week 6 we have;

H = 4.5 + 6×1.4 = 12.9 inches

Which indicates that Plant A will be 0.9 inches taller than Plant B at week 6.

The correct option is therefore;

No, The greater rate of change of Plant A will result in it being 0.9 inches taller in 6 weeks.

5 0
3 years ago
Read 2 more answers
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