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sergij07 [2.7K]

3 years ago

11

A computer company uses the function f(h) = 50h + 75 to calculate the total repair bill, f(h), for h number of hours worked. Fin

d h if f(h) = $275.
13,825 hours
13,750 hours
4 hours
2 hours

2 answers:

Andre45 [30]3 years ago

6 0

4 hours is the answer to your question.

IgorLugansk [536]3 years ago

5 0

4 Hours because 50 times 4 is 200 and 200+75 is 275

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Find the appropriate rejection regions for the large-sample test statistic z in these cases. (Round your answers to two decimal

Usimov [2.4K]

Answer:

a) We have that the significance is given by $\alpha =0.01$ and we know that we have a right tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 1% of the area on the right and 99% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.01,0,1)"

And we got for this case $z_{crit}=2.33$

So then the rejection region would be $z>2.33$

b) We have that the significance is given by $\alpha =0.05$ , $\alpha/2 =0.025$ and we know that we have a two tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 2.5% of the area on the right and 97.5% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.025,0,1)"

And we got for this case $z_{crit}=\pm 1.96$

So then the rejection region would be $z>1.96 \cup z$

Step-by-step explanation:

Part a

We have that the significance is given by $\alpha =0.01$ and we know that we have a right tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 1% of the area on the right and 99% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.01,0,1)"

And we got for this case $z_{crit}=2.33$

So then the rejection region would be $z>2.33$

Part b

We have that the significance is given by $\alpha =0.05$ , $\alpha/2 =0.025$ and we know that we have a two tailed test.

So for this case we need to look in the normal standard dsitribution a critical value that accumulates 2.5% of the area on the right and 97.5% of the area on the left. This value can be founded with the following excel code:

"=NORM.INV(1-0.025,0,1)"

And we got for this case $z_{crit}=\pm 1.96$

So then the rejection region would be $z>1.96 \cup z$

7 0

4 years ago

Vidriana rolled a number cube 96 times. Her results are shown in the table, what is the experimental probability of rolling an e

hichkok12 [17]

Answer:

50/96

Step-by-step explanation:

I assume the table is:

$\left[\begin{array}{cc}Result&Total\\1&15\\2&13\\3&16\\4&17\\5&15\\6&20\end{array}\right]$

Even numbers are 2, 4, and 6. The total number of times she rolled an even number is 13 + 17 + 20 = 50.

So the probability is 50/96.

7 0

3 years ago

The admissions office of a private university released the following admission data for the preceding academic year: From a pool

lina2011 [118]

Answer: Our required probability is 0.1695.

Step-by-step explanation:

Since we have given that

Number of male applicants = 4200

Number of female applicants = 3800

So, total number of applicants = 4200+3800 = 8000

Probability of male entered and subsequently enrolled is given by

$0.4\times 0.4=0.16$

Probability of female entered and subsequently enrolled is given by

$0.4\times 0.45\\\\=0.18$

Number of male entered and subsequently enrolled is given by

$0.16\times 4200\\\\=672$

Number of female entered and subsequently enrolled is given by

$0.18\times 3800\\\\=684$

So, Probability that a student who applied for admission will be accepted by the university and subsequently will enroll is given by

$\dfrac{672+684}{8000}\\\\=\dfrac{1356}{8000}\\\\=0.1695$

Hence, our required probability is 0.1695.

3 0

3 years ago

Calculate the insurance costs.

d1i1m1o1n [39]

You really just need the little table they provide to figure this one out, but here we go!
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4 0

3 years ago

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PLS HELP, Yesterday 5/8 of the 64 students in a contest give their speeches. How many students do their speeches, Simplest form

Alexxandr [17]

Answer:

40 students have given their speeches

24 students need to give their speeches

5/8 of the students have given their speeches

3/8 of the students need to give their speeches

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers