Answer:
One real root
Step-by-step explanation:
By the fundamental theorem of algebra, an nth degree polynomial has n-possible real roots.
If there are complex roots, then the the complex roots come in pairs.
Therefore the number of possible real roots of are 3 real roots with no complex pairs or 1 real root with a complex pair.
By Descartes rule of signs, there is only one change of sign in the polynomial (+ to -).
Hence there is only one positive real root.
There is change is sign two times but we can not have even number of real roots for this polynomial
Therefore there is only real root.