1) 5t^2 (1 + 6t)
2) 4x^3y^5 (5x + 2y)
3) (5r + 6x)(5r - 6x)
4) (x + 10)(x - 10)
5) (x - 3)^2
6) (x -5)(x - 3)
7) 3(16r^3 + 9)
8) 8(c^3 + 8d^3)
9) (2r - 125)(4r^2 + 250r + 15625)
10) (c + 3)(c - 1)
Answer:
k = 12
Step-by-step explanation:
Given:
The equation 
To find:
Value of 
for which the given equation has one distinct real solution.
Solution:
The given equation is a quadratic equation.
There are always two solutions of a quadratic equation.
For the equation: 
to have one distinct solution:
Here,
a = 2,
b = -k and
c = 18
Putting the values, we get:
The equation becomes:
And the one root is:
Knowing what the variables are means that all we have to do is substitute:
[ ( 3 ) ^2 + ( 4 ) ^2 ] / 4 - 3 =
( 9 + 16 ) / 1 =
25
Answer:
hmmmm I don't know It really depends on the person who is writing it
Step-by-step explanation:
but if you really want to know most people have different ways of telling people how they got to their answer
