linear equation that passes through the two points (-6, -7) and (3, -4) is ![y=\frac{1}{3}x-5](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B1%7D%7B3%7Dx-5)
Step-by-step explanation:
We need to write the equation that passes through the two points (-6, -7) and (3, -4).
The equation can be written is point slope form.
The standard form of point slope equation is:
![y=mx+b](https://tex.z-dn.net/?f=y%3Dmx%2Bb)
where m is the slope and b is the y-intercept
Finding slope m:
Slope can be found by using formula:
![slope = \frac{y_{2}-y_{1}}{x{2}-x_{1}} \\Where\,\, y_{2}=-4,y_{1}=-7,x{2}=3,x_{1}=-6\\slope =\frac{-4-(-7)}{3-(-6)}\\slope=\frac{-4+7}{3+6}\\slope=\frac{3}{9}\\slope=\frac{1}{3}](https://tex.z-dn.net/?f=slope%20%3D%20%5Cfrac%7By_%7B2%7D-y_%7B1%7D%7D%7Bx%7B2%7D-x_%7B1%7D%7D%20%5C%5CWhere%5C%2C%5C%2C%20y_%7B2%7D%3D-4%2Cy_%7B1%7D%3D-7%2Cx%7B2%7D%3D3%2Cx_%7B1%7D%3D-6%5C%5Cslope%20%3D%5Cfrac%7B-4-%28-7%29%7D%7B3-%28-6%29%7D%5C%5Cslope%3D%5Cfrac%7B-4%2B7%7D%7B3%2B6%7D%5C%5Cslope%3D%5Cfrac%7B3%7D%7B9%7D%5C%5Cslope%3D%5Cfrac%7B1%7D%7B3%7D)
So, slope is ![\frac{1}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B3%7D)
Now finding y-intercept b
Putting slope
and point(-6,-7)
![y=mx+b\\x=-6,y=-7,m=\frac{1}{3} \\-7=\frac{1}{3}(-6)+b\\-7=-2+b\\b=-7+2\\b=-5](https://tex.z-dn.net/?f=y%3Dmx%2Bb%5C%5Cx%3D-6%2Cy%3D-7%2Cm%3D%5Cfrac%7B1%7D%7B3%7D%20%5C%5C-7%3D%5Cfrac%7B1%7D%7B3%7D%28-6%29%2Bb%5C%5C-7%3D-2%2Bb%5C%5Cb%3D-7%2B2%5C%5Cb%3D-5)
So, value of b is -5
Putting values to find the equation:
![y=mx+b\\m=\frac{1}{3} and b=-5\\y=\frac{1}{3}x-5](https://tex.z-dn.net/?f=y%3Dmx%2Bb%5C%5Cm%3D%5Cfrac%7B1%7D%7B3%7D%20and%20b%3D-5%5C%5Cy%3D%5Cfrac%7B1%7D%7B3%7Dx-5)
So, linear equation that passes through the two points (-6, -7) and (3, -4) is ![y=\frac{1}{3}x-5](https://tex.z-dn.net/?f=y%3D%5Cfrac%7B1%7D%7B3%7Dx-5)
Keywords: Linear Equation,
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