What are all these answers

Mathematics

1 answer:

Xelga [282]4 years ago

8 0

Number is an isosceles triangle number seven is a right angle triangle number 9 I believe is a scalene triangle number 10 is a right angle triangle I also believe 11 is a scalene triangle and I believe number 8 is equilateral triangle

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A helpful hand please

Tpy6a [65]

$\bf s=\sqrt{2gh}\quad 
\begin{cases}
s=speed\\
g=gravity\\
h=height\\
-----\\
s=34\\
g=32
\end{cases}\implies s^2=2gh\\\\\\ \cfrac{s^2}{2g}=h\implies \cfrac{34^2}{2\cdot 32}=h$

3 0

4 years ago

Perform the following matrix operation?

adell [148]

Answer:

You can't add those two matrices as they do not have the same dimensions

Step-by-step explanation:

This also relates to subtraction as well (you need to have same dimensions)

3 0

3 years ago

Read 2 more answers

Anybody know the right answer?

qwelly [4]

Quadrant I : cot(x) > 0 → -cot(x) < 0

Quadrant II : cot(x) < 0 → -cot(x) > 0

Quadrant III : cot(x) > 0 → -cot(x) < 0

Quadrant IV : cot(x) < 0 → -cot(x) > 0

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$a)\ \left(\dfrac{11\pi}{6},\ -\sqrt3\right)\\\\\dfrac{11\pi}{6}\in\text{Quadrant IV, then -cot(x)} > 0,\ \text{we have}\ -\cot\dfrac{11\pi}{6}=-\sqrt3 < 0$

Answer: a)

$b)\\\dfrac{2\pi}{3}\in\text{Quadrant II},\ -\cot(x) > 0,\ \text{we have}\ \dfrac{\sqrt3}{3} > 0\\\\c)\\\dfrac{5\pi}{4}\in\text{Quadrant III},\ -\cot(x) < 0,\ \text{we have}\ -1 < 0\\\\d)\\\dfrac{4\pi}{3}\in\text{Quadrant III},\ -\cot(x) < 0,\ \text{we have}\ -\dfrac{\sqrt3}{3} < 0$