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jolli1 [7]
3 years ago
8

A rental moving truck can haul a maximum of 7,500 pounds. Dejuan has boxes that weigh 40 pounds and boxes that weigh 75 pounds.

How many of each kind of box can he haul in one load?
Mathematics
1 answer:
Lelechka [254]3 years ago
8 0

Answer:

One hundred and fifty 40 pounds boxes and twenty 75 pounds boxes

Step-by-step explaination:

The maximum amount he can haul in one load is 7500 pounds

150 × 40 pounds boxes = 6000 pounds

20 × 75 pounds boxes = 1500 pounds

6000 pounds + 1500 pounds = 7500 pounds

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a local basketball court dimensions are 50 ft long, 20 ft wide, the court is lost square footage by 1/4. what are the new dimens
VikaD [51]
50x20=1000

1000x(1/4)=250

1000-250=750ft^2
3 0
3 years ago
Item 16 A sphere has a radius of 8 centimeters. A second sphere has a radius of 2 centimeters. What is the difference of the vol
Zigmanuir [339]

Answer:

672\pi \text{ cm}^3.

Step-by-step explanation:

We have been given that a sphere has a radius of 8 centimeters. A second sphere has a radius of 2 centimeters. We are asked to find the difference of the volumes of the spheres.      

We will use volume formula of sphere to solve our given problem.

\text{Volume of sphere}=\frac{4}{3}\pi r^3, where r is radius of sphere.

The difference of volumes would be volume of larger sphere minus volume of smaller sphere.

\text{Difference of volumes}=\frac{4}{3}\pi(\text{8 cm})^3-\frac{4}{3}\pi(\text{2 cm})^3

\text{Difference of volumes}=\frac{4}{3}\pi(512)\text{ cm}^3-\frac{4}{3}\pi(8)\text{ cm}^3

\text{Difference of volumes}=\frac{4}{3}\pi(512-8)\text{ cm}^3

\text{Difference of volumes}=4\pi(168)\text{ cm}^3

\text{Difference of volumes}=672\pi\text{ cm}^3

Therefore, the difference between volumes of the spheres is 672\pi \text{ cm}^3.

3 0
3 years ago
Natalie uses 68 photos to make an online photo album. She can fit 5 photos on each page. She fills all of the pages in her album
Sati [7]
68-2(\5)=#of pages in album
6 0
4 years ago
A certain shop repairs both audio and video components. Let A denote the event that the next
alexdok [17]

Answer:

0.12 is the required probability.

Step-by-step explanation:

We are given the following in the question:

A: next  component brought in for repair is an audio component

B: event that the next component  is a compact disc player

B \in A

P(A)= 0.6\\P(B) =0.05

We have to evaluate:

P(B|A) = \dfrac{P(B\cap A)}{P(A)}\\P(B|A) = \dfrac{P(B)}{P(A)}\\\\P(B|A) = \dfrac{0.05}{0.6} = 0.12

0.12 is the required probability.

3 0
3 years ago
What's the answer of 13846+8273636-3763x8273736
ipn [44]
13846+8273636
= 8287482

8287482-3763
=8283719

8283719x8273736
=6.8537304^13
7 0
3 years ago
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