1.) Group like terms: 4x+3x-5x+5x+5x-3x+2x-8x+2x-5x-5+7
2.) Add similar elements: = 4x+3x-5x+5x+5x-3x+2x-8x+2x-5x=0
3.) =-5+7
4.) Add/Subtract the numbers: -5 + 7 = 2
<u>Your Answer: 2</u>
Answer:
The ship's horizontal distance from the lighthouse is approximately 1,303.03 feet.
Step-by-step explanation:
The nearest tenth would be 10.1
Answer:
x = 28.01t,
y = 10.26t - 4.9t^2 + 2
Step-by-step explanation:
If we are given that an object is thrown with an initial velocity of say, v1 m / s at a height of h meters, at an angle of theta ( θ ), these parametric equations would be in the following format -
x = ( 30 cos 20° )( time ),
y = - 4.9t^2 + ( 30 cos 20° )( time ) + 2
To determine " ( 30 cos 20° )( time ) " you would do the following calculations -
( x = 30 * 0.93... = ( About ) 28.01t
This represents our horizontal distance, respectively the vertical distance should be the following -
y = 30 * 0.34 - 4.9t^2,
( y = ( About ) 10.26t - 4.9t^2 + 2
In other words, our solution should be,
x = 28.01t,
y = 10.26t - 4.9t^2 + 2
<u><em>These are are parametric equations</em></u>
