3 years ago

(16x+14)-(3x^2+-19)

Mathematics

1 answer:

oksian1 [2.3K]3 years ago

8 0

The answer is -3x^2+16x+33.

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$given \: complementary \: angles \: add \: up \: to \: 90 \: degrees \\ then \\ 2p + 6 + 4p = 90 \\ 6p + 6 = 90 \\ 6(p + 1) = 90 \\ p + 1 = \frac{90}{6} \\ p + 1 = 15 \\ p = 15 - 1 \\ p = 14$

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(16x+14)-(3x^2+-19)​

(16x+14)-(3x^2+-19)