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gladu [14]
4 years ago
11

How do you do long division for thousands

Mathematics
1 answer:
faltersainse [42]4 years ago
7 0

Answer: For example if it is a number such as 45,212 and you are dividing it by 20. Ignore the 212 until you get rid of the 45 then go from there.

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Eliminate the parameter
8090 [49]

<u> </u>y = x -2, x\geq 1

<u>Step-by-step explanation:</u>

In the question given correct parameter is -  2)  y = x -2, x\geq 1

Method -

x= t^2 + 1    ........................(1)

y = t^2 - 1  ..........................(2)

Let's solve the equation 1,

⇒   x = t^2 +1

⇒   t^2 = x - 1          

  •         Put the value of  t² in equation 2

                  y =t^2 - 1 \\y = x -1 -1\\y = x - 2

      <u>Here we got the y parameter as </u>y = x -2

<u>So the option no .2 is the correct option</u> 2) <u> </u>y = x -2, x\geq 1

4 0
3 years ago
Jackie has 1/3 of a Hershey bar.steven has 4/12 of a Hershey bar.How much do they have together?
Alisiya [41]
Since Jackie has 1/3 and Steven has 4/12 we add them together


4/12+1/3= 2/3

Together they have 2/3 of a Hershey Bar
8 0
3 years ago
Read 2 more answers
Question:
prohojiy [21]
Let f(x) = p(x)/q(x), where p and q are polynomials and reduced to lowest terms. (If p and q have a common factor, then they contribute removable discontinuities ('holes').) 
Write this in cases: 
(i) If deg p(x) ≤ deg q(x), then f(x) is a proper rational function, and lim(x→ ±∞) f(x) = constant. 
If deg p(x) < deg q(x), then these limits equal 0, thus yielding the horizontal asymptote y = 0. 
If deg p(x) = deg q(x), then these limits equal a/b, where a and b are the leading coefficients of p(x) and q(x), respectively. Hence, we have the horizontal asymptote y = a/b. 
Note that there are no obliques asymptotes in this case. ------------- (ii) If deg p(x) > deg q(x), then f(x) is an improper rational function. 
By long division, we can write f(x) = g(x) + r(x)/q(x), where g(x) and r(x) are polynomials and deg r(x) < deg q(x). 
As in (i), note that lim(x→ ±∞) [f(x) - g(x)] = lim(x→ ±∞) r(x)/q(x) = 0. Hence, y = g(x) is an asymptote. (In particular, if deg g(x) = 1, then this is an oblique asymptote.) 
This time, note that there are no horizontal asymptotes. ------------------ In summary, the degrees of p(x) and q(x) control which kind of asymptote we have. 
I hope this helps!
4 0
3 years ago
Multiply and combine like terms to determine the product of these polynomials. (3x−6)(4x+1)
icang [17]
0.12 I think I’m not sure how to do this I ji at have an idea maybe I’m super wrong
5 0
3 years ago
Read 2 more answers
use this information for items 1-3. Aaron has $65 to rent a bike in the city . It costs $15 per hour to rent a bike. The additio
marissa [1.9K]

Answer:

<h2>You will ride for 4 hrs 8min</h2>

Step-by-step explanation:

What we are expected to solve for that the problem did not expressly state is most likely the number of hours that you could ride for an amount of $65.

firstly we need to model the inequality (equation) for this scenario.

the constant fee= $3 additional fee for helmet

3+15n\leq 65\\\\

We can now solve for n since the above inequality satisfies the condition presented in the problem statement.

 3+15n\leq 65\\\\15n\leq65-3\\\\ 15n\leq 62

Divide both sides by 15 to find n

n\leq 62/15\\\\n\leq 4hrs -8min

8 0
3 years ago
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