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3 years ago

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Aaron wants to go car shopping. He wants to buy different models all at the same price. He buys 3 Lincolns, 5 Fords, and 10 BMWs

. If he spends a total of $119,772, how much were each of the cars that he purchased?

1 answer:

ExtremeBDS [4]3 years ago

8 0

The answer is $6.654, that’s the price for each car. You just divide 119.772 / the number of cars. Hope it helped.

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Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

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And p is the probability of X happening.

In this problem, we have that:

12% of children are nearsighted. This means that $p = 0.12$ .

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There are 18 students, so $n = 18$

This probability is:

$P = P(X = 0) + P(X = 1)$

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So

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