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3 years ago

9

Write two equivalent ratios using four different types of music in the data table showing. How do you know the ratios are equiva

lent?
rock-12
classic rock-4
county-18
jazz-2
heavy metal-6

2 answers:

Murrr4er [49]3 years ago

6 0

6/12, 2/4, 2/18, 2/12
These are equivalent because in a way they equal each other with division

Licemer1 [7]3 years ago

3 0

6/12, 2/4, 2/18, 2/12

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Find the constant difference for a hyperbola with foci (-3.5, 0) and (3.5, 0) and a point on the hyperbola (3. 5, 24).

Solnce55 [7]

Answer:

2a=1

Step-by-step explanation:

The constant difference for a hyperbola $\dfrac{x^2}{a^2}-\dfrac{y^2}{b^2}=1$ is $2a.$

1. Since hyperbola has foci (-3.5, 0) and (3.5, 0), then $c=3.5.$ Note that $c=\sqrt{a^2+b^2},$ then

$\sqrt{a^2+b^2}=3.5\Rightarrow a^2+b^2=3.5^2.$

2. Since point (3.5,24) lies on the hyperbola, then

$\dfrac{3.5^2}{a^2}-\dfrac{24^2}{b^2}=1.$

3. Solve the system of two equations:

$\left\{\begin{array}{l}a^2+b^2=3.5^2\\\dfrac{3.5^2}{a^2}-\dfrac{24^2}{b^2}=1\end{array}\right.$

From the 1st equation,

$b^2=3.5^2-a^2,$

then

$\dfrac{3.5^2}{a^2}-\dfrac{24^2}{3.5^2-a^2}=1,\\ \\\dfrac{3.5^2(3.5^2-a^2)-24^2a^2}{a^2(3.5^2-a^2)}=1,\\ \\3.5^4-3.5^2a^2-24^2a^2=3.5^2a^2-a^4,\\ \\a^4-a^2(2\cdot 3.5^2+24^2)+3.5^4=0,\\ \\a^4-600.5a^2+150.0625=0,\\ \\D=(-600.5)^2-4\cdot 150.0625=360000,\\ \\a^2_{1,2}=\dfrac{600.5\pm 600}{2}=\dfrac{1}{4},600\dfrac{1}{4}.$

For $a^2=\dfrac{1}{4},\ b^2=3.5^2-0.25=12.$

For $a^2=600\dfrac{1}{4},\ b^2=3.5^2-600.25$ this is impossible, then $a^2=600\dfrac{1}{4}$ is extra solution.

Hence, $a=\dfrac{1}{2}$ and $2a=1.$

5 0

3 years ago

WILL GIVE BRAINLIEST!!!

ella [17]

Answer:

The answer is C.) m∠RCD = m∠ACD ÷ 2

RCD = ACD divided by two.

RCD = 90 degrees

ACD ÷2 = 180÷2 = 90 degrees.

So, your answer is C.

Hope this helped. Have a grey day!

4 0

3 years ago

Hi please do this answer and please show the (steps) on how you got it. ❤️

zhenek [66]

This is the answer!!!!!!

4 0

3 years ago

For the figures below, assume they are made of semicircles, quarter circles and squares. For each shape, find the area and perim

ASHA 777 [7]

The area of the given figure is 576 cm sq.

The perimeter of the given figure is 96 cm.

Step-by-step explanation:

The shape consists of one semicircle and one square which is cut by a semicircle.

<u>To find Area:</u>

Find the area of semicircle= (πr^2)/2

where r is the radius= diameter/2= 24/2= 12 cm

Area of semicircle= π(12)(12)/2= 144π/2= 72π cm sq.

Find the area of square= a^2

where a is the side of square, a=24 cm.

Area of the square= 24*24= 576 cm sq.

To find the total area of the given figure,

Area of the figure= Area of semicircle+(area of square- area of semicircle)

= 72π+576-72π =576 cm sq.

<u>To find perimeter:</u>

Perimeter of semicircle= (2πr)/2

= (2*12*π)/2= 12π cm

Perimeter of square= 4a =4*24 =96 cm

Perimeter of the given figure= perimeter of semicircle+(perimeter of square- perimeter of semicircle)

= 12π+96+12π =96 cm.

4 0

3 years ago

I didn’t study and it’s 2 am pls help

AlexFokin [52]

Answer: 7. g = -50, 8. f= 340/6 9. 3 10 .125

Step-by-step explanation:#7 g(3): 4(3)^2 +6 =12^2 +6 = 1444=6= 150. We divide 150 by 3 giving us -50. #8We start by putting f(6): -3(6)^2 -4(6) +8. We use PEMDAS. -18^2 -24 +8 = _324-24+8 F= 340/6 #9 g(15) = Square root of 15-6=9 and the square root of 9 is 3, therefore, the answer is 3. #10 h (x) = 2^x we plug -3 to 2^-3. It is a negative number and it gives us .125 or 12.5

3 0

3 years ago

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