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Fofino [41]
2 years ago
13

Help

Mathematics
1 answer:
Art [367]2 years ago
5 0

\huge\fbox{Answer ☘}

\bold{3( \frac{27}{8} ) {}^{ \frac{2}{3}  \times  - 1}  = 2( \frac{32}{243} ) {}^{2x} }\\  \\3(( \frac{3}{2} ) {}^{3} ) {}^{ \frac{2}{3} \times  - 1 }  = 2(( \frac{2}{3} ) {}^{5} ) {}^{2x}  \\\\ 3( \frac{3}{2} ) {}^{2 \times  - 1}  = 2( \frac{2}{3} ) {}^{10x}  \\\\ 3( \frac{2}{3} ) {}^{2}  = 2( \frac{2}{3} )  {}^{10x}  \\\\ 3( \frac{4}{9} ) = 2( \frac{4}{9} ) {}^{5x}  \\\\\bold\pink{ comparing \: powers }\\\\5x = 1 \\\\ \bold\blue{x =  \frac{1}{5} }

hope helpful~

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