1. To solve this problem you must sum the volume of the cone and the volume of the hemisphere. This means that the volumen of the prop is:
Vt=Vc+Vh
Vt is the volumen of the prop.
Vc is the volumen of the cone.
Vh is the volume of the hemisphere.
2. The volume of the cone (Vc) is:
Vc=1/3(πr²h)
r=9 in
h=14 in
π=3.14
4. Then, you have:
Vc=(3.14)(9 in)²(14 in)/3
Vc=3560.76 in³/3
Vc=1186.92
5. The volume of the hemisphere (Vh) is:
Vh=2/3(πr³)
π=3.14
r=9 in
6. Then, you have:
Vh=(2)(3.14)(9 in)³/3
Vh=4578.12 in³/3
Vh=1526.04 in³
7. Finally, the volumen of the prop (Vt) is:
Vt=Vc+Vh
Vt=1186.92 in³+1526.04 in³
Vt=2713.0 in³
<span>
What is the volume of the prop?
</span>
The volume of the prop is 2713.0 in³
Answer:
it can`t be solved unless you have an integer in place of F and B
otherwise this can`t be solved
Answer:
96 and 36
Step-by-step explanation:
3+8 = 11
132/11 = 12
so:
12 x 3 = 36
12 x 8 = 96
Fractions Area Volume length h
Answer:
Domain = (1,3,5,8) and Range = (2, 4, 6, 9)
Step-by-step explanation:
Domain are sets of input values
Range are set of output values that have a corresponding values in the domain
From (domain, range)
Therefore, the domain are: (1,3,5,8)
Range are: (2,4,6,9
