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Degger [83]
4 years ago
5

Which angles are obtuse?

Mathematics
2 answers:
mario62 [17]4 years ago
5 0

Answer:

B. ∠DBC

Step-by-step explanation:

∠DBA is an acute angle

∠GFE is also an acute angle

∠MLK is a right angle, neither acute or obtuse (it's in its own category)

Vaselesa [24]4 years ago
5 0

Answer:

B. ∠DBC

Step-by-step explanation:

Obtuse angles are angles larger than 90 degrees.

We can easily tell that ∠GFC and ∠MLK aren't obtuse, since ∠GFC is acute and ∠MLK is a right angle. <u><em>Right angles and acute angles are always less than obtuse.</em></u>

<u><em /></u>

Now, for a trickier one. Let's look at ∠DBA and ∠DBC

It's easer to find out what type of angles they are by separating them. (look at image)

See? ∠DBA is acute. And we can easily tell that ∠DBC is an obtuse angle.

<h3><em><u></u></em></h3><h3><em><u>Hence, ∠DBC is the correct answer</u></em></h3><h3><em><u></u></em></h3><h2>Hope this helps! (Brainliest?)</h2>

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Tell whether (1,-1) is a solution of y<br> 9x - 10
posledela

Answer:

yes, it is

Step-by-step explanation:

plug in the point (1, -1) (x,y) into the equation y = 9x - 10

-1 = 9(1)-10

-1 = 9-10

-1=-1

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3 years ago
HELLLLLPPPPP: ANSWER CHOICES BELOW:
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he polynomial x(5x² + 10x + 15), it is not completely factored, 5x² + 10x + 15 can still be factored into two binomials.

<h3>Polynomial</h3>

Polynomial is an expression that involves only the operations of <em>addition, subtraction, multiplication </em>of variables.

Given the polynomial x(5x²+10x+15), it is not completely factored, 5x²+10x+15 can still be factored,

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3 years ago
What is the range of function y=√(-2cos^2x+3cosx-1)
Ugo [173]
Hello Friend,here is the solution for your question


<span>so the given function is </span>
y= √(-2cos²x+3cosx-1)
 i.e = √[-2(cos²x-3/2+1/2)]
i.e = √[-2(cosx-3/4)²-9/16+1/2]
i.e. = √[-2(cos-3/4)²-1/16]
i.e. = √[1/8-3(cosx=3/4)²]-----------(1)

Now here  in this equation is this quantity :-
<span>(cosx=3/4)²----------------(2)   is to it's minimum value then the whole equation </span>
<span>i.e. = √[1/8-3(cosx=3/4)²] will be maximum and vice versa </span>


And we know that cosx-3/4 will be minimum if cosx=3/4
<span>therefore put this in (1) we get </span>
(cosx=3/4)²=0    [ cosx=3/4]
<span>hence the minimum value of the quantity (cosx=3/4)² is 0 </span>

<span>put this in equation (1) </span>
we get ,
i.e. = √[1/8-3(cosx=3/4)²]
   =√[1/8-3(0)]        [ because minimum value of of the quantity (cosx=3/4)² is 0 ]
     =√1/8
      =1/(2√2)

<span>this is the maximum value now to find the minimum value </span>

<span>since this is function of root so the value of y will always be ≥0 </span>

<span>hence the minimum value of the function y is 0 </span>


<span>Therefore, the range of function </span>y is [0,1/(2√2)]


__Well,I have explained explained each and every step,do tell me if you don't understand any step._

8 0
3 years ago
Consider a circle whose size can vary. Let r r represent the radius of the circle (in cm) and let C C represent the circumferenc
Ket [755]

Answer:

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Step-by-step explanation:

You know the formula for circumference in terms of radius is ...

  C = 2πr

You are being asked to write this as a function named "f". That will be ...

  f(r) = 2πr

8 0
4 years ago
Read 2 more answers
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