Subtract. (4x + 7) - (x+1) A. 3x + 8 B. 3x + 6 C. 4x + 8 O D. 4x + 6 Lmk
2 answers:
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Answer:
Part 1)
Part 2)
Step-by-step explanation:
Part 1) Find the area
we know that
The area of the shape is equal to the area of a quarter of circle minus the area of an isosceles right triangle
so
we have that the base and the height of triangle is equal to the radius of the circle
substitute
simplify
Factor 36
Part 2) Find the perimeter
The perimeter of the figure is equal to the circumference of a quarter of circle plus the hypotenuse of the right triangle
<em>The circumference of a quarter of circle is equal to</em>
substitute the given values
The hypotenuse of right triangle is equal to (applying the Pythagorean Theorem)
simplify
Find the perimeter
simplify
Factor 6
You solve the equation : t^2 - 9t - 90 = 0 ;
Δ = ( - 9 )^2 - 4 * 1 * ( - 90 ) = 81 + 360 = 441 ;
t1 = ( 9 +
) / 2 = 30 / 2 = 15 ;
t2 = ( 9 -) / 2 = -12 / 2 = - 6 ;
The numbers are 15 and - 6 ;
Δ = ( - 9 )^2 - 4 * 1 * ( - 90 ) = 81 + 360 = 441 ;
t1 = ( 9 +
t2 = ( 9 -
The numbers are 15 and - 6 ;