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Studentka2010 [4]
3 years ago
5

Subtract. (4x + 7) - (x+1) A. 3x + 8 B. 3x + 6 C. 4x + 8 O D. 4x + 6 Lmk

Mathematics
2 answers:
Studentka2010 [4]3 years ago
8 0

Answer:

4x + 7 - ( x + 1)

Remove the bracket

We get

4x + 7 - x - 1

= 3x + 6

That's option B

Hope this helps.

Naddika [18.5K]3 years ago
6 0

(4x + 7) - (x+1)

Remove the brackets and distribute the negative sign to x+1.

4x + 7 - x - 1

4x - x + 7 - 1

Add or subtract like terms.

<h2>3x + 6</h2>

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(5x4 + 5x3 + 4x - 9) + (2x4 + 7x2 + 2x + 14)
ladessa [460]

Answer:

7x⁴ + 5x³ + 7x² + 6x + 5

Step-by-step explanation:

The given expression is

(5x4 + 5x3 + 4x - 9) + (2x4 + 7x2 + 2x + 14)

The first step is to open the brackets by multiplying each term inside each bracket by the term outside each bracket. Since the term outside each bracket is 1, the expression becomes

5x⁴ + 5x³ + 4x - 9 + 2x⁴ + 7x² + 2x + 14

We would collect like terms by combining each term with the same exponent or raised to the same power. The term would be arranged in decreasing order of the exponents. It becomes

5x⁴ + 2x⁴ + 5x³ + 7x² + 4x + 2x - 9 + 14

7x⁴ + 5x³ + 7x² + 6x + 5

7 0
3 years ago
Angela is following this recipe to make biscuits.
maks197457 [2]

Answer : The amount of margarine needed is 1 kg.

Step-by-step explanation :

First we have to convert volume of syrup from mL to L.

Conversion used:

1 L = 1000 mL

or, 1 mL = 0.001 L

So, 225 mL = 0.225 L

Now we have to calculate the amount of margarine needed.

As, 0.225 L of syrup needed 150 g of margarine

So, 1.8 L of syrup needed \frac{1.5L}{0.225L}\times 150 g=1000g of margarine

Amount of margarine needed = 1000 g = 1 kg     (1 kg = 1000 g)

Therefore, the amount of margarine needed is 1 kg.

4 0
3 years ago
8 3/4 ÷ (-3 1/2) PLS I NEED HELP
Basile [38]

Answer:

you could have used a calculator

Step-by-step explanation:

-2.8

7 0
3 years ago
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Solve by completing the square. Round your answers to the nearest tenth and then locate the greater solution. <img src="https://
Andrews [41]

Step-by-step explanation:

Step 1: Write our Givens

{x}^{2}  + 10x - 7 = 0

Move the constant term ,(the term with no variable) to the right side.

Here we have a negative 7, so we add 7 to both sides

{x}^{2}  + 10x = 7

Next, we take the linear coeffeicent and divide it by 2 then square it.

( \frac{10}{2} ) {}^{2}  = 25

Then we add that to both sides

{x}^{2}  + 10x + 25 = 7 + 25

{ {x}^{2} } + 10x + 25 = 32

Next, we factor the left,

(x + 5)(x + 5) = 32

we got 5 because 5 add to 10 and multiply to 25 as well.

so we get

(x + 5) {}^{2}  = 32

This is called a perfect square trinomial.

Next, we take the square root of both sides

x + 5 = ± \sqrt{32}

± menas that we have a positive and negative solution.

Subtract 5 form both side so we get

x =  - 5± \sqrt{32}

The greater solution is when sqr root of 32 is positive so the answer to that is

\sqrt{32}  - 5 = 0.7

3 0
2 years ago
What does gemdas and pemdas stands for?
DanielleElmas [232]

Answer:

For pemdas

P Parentheses

E Exponents

M Multiplication

D Division

A Addition

S Subtraction

And for gemdas

G Grouping

E Exponents

M Multiplication

D Division

A Addition

S Subtraction

8 0
3 years ago
Read 2 more answers
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