Answer:
f(g) = -15x^2 + 15x + 2.
g(-2) = 18.
Step-by-step explanation:
f(g) = -5(3x^2 - 3x) + 2
= -15x^2 + 15x + 2.
g(-2) = 3(-2)^2 - 3(-2)
= 12 + 6
= 18.
Answer:
0.2364
Step-by-step explanation:
We will take
Lyme = L
HGE = H
P(L) = 16% = 0.16
P(H) = 10% = 0.10
P(L ∩ H) = 0.10 x p(L U H)
Using the addition theorem
P(L U H) = p(L) + P(H) - P(L ∩ H)
P(L U H) = 0.16 + 0.10 - 0.10 * p(L u H)
P(L U H) = 0.26 - 0.10p(L u H)
We collect like terms
P(L U H) + 0.10P(L U H) = 0.26
This can be rewritten as:
P(L U H)[1 +0.1] = 0.26
Then we have,
1.1p(L U H) = 0.26
We divide through by 1.1
P(L U H) = 0.26/1.1
= 0.2364
Therefore
P(L ∩ H) = 0.10 x 0.2364
The probability of tick also carrying lyme disease
P(L|H) = p(L ∩ H)/P(H)
= 0.1x0.2364/0.1
= 0.2364
Answer:
Option (4)
Step-by-step explanation:
Area of a triangle = 
Where a and b are the sides of a triangle and θ is the angle between the sides a and b.
By this rule,
Area of ΔWZY = 
45 = 
9 = (YZ).Sin(115)°
YZ = 
YZ = 9.93
Perimeter of parallelogram WXYZ = WX + XY + YZ + WZ
= 9.93 + 10 + 9.93 + 10
= 39.86
≈ 40 units
Therefore, perimeter of the parallelogram is 40 units.
Option (4) is the answer.
Hello.
Taking a look at our screenshot provided, we can conclude that we need to find the missing angle degree out of 90 degrees, as we are dealing with a right angle.
Let's set this up as an Algebraic formula and solve for the variable;
5x + 15 + 50 = 90
First, let's combine like-terms (15 and 50).
5x + 65 = 90
Now, isolate our variable by subtracting 65 from each side of the equation.
90 - 65 = 25
65 - 65 = 0
5x = 25
Now, divide both sides by 5 to solve for x, our missing angle degree.
x = 5
Your answer is A.) 5
I hope this helps!
Answer:
Within 0.5 of ;
is not ;
Step-by-step explanation:
Given the data:
The actual standard deviation, = 1
;
The range rule of thumb to estimate the value if standard deviation is ;
Estimated standard deviation = Range / 4
The range = (maximum - minimum) values
The estimated standard deviation = 4 / 4 = 1
Hence, the estimated standard deviation is with 0.5 of the actual standard deviation, Thus, the estimated standard deviation is not substantially different from the actual standard deviation.
