Answer:
the limit does not exist
Step-by-step explanation:
As x approaches π/2 from below, tan(x) approaches +∞. A x approaches π/2 from above, tan(x) approaches -∞. These two limits are not the same, so the limit is said not to exist.
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For a limit to exist, it must be the same regardless of the direction of approach.
A.
6/9 + 6/9 = 12/9
Hope this helps!!!
Answer:
Step-by-step explanation:
1. x = 11.2
2. 13
3. 9
4. -7/15
5. 15b
6. -12x + 16
7. 4x + 4
8. 11x-10
9. 10a + 5
10. -x, 15, and 2b
Hope that helps, and good luck!
We can rewrite the expression under the radical as
then taking the fourth root, we get
![\sqrt[4]{\left(\dfrac32a^2b^3c^4\right)^4}=\left|\dfrac32a^2b^3c^4\right|](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7B%5Cleft%28%5Cdfrac32a%5E2b%5E3c%5E4%5Cright%29%5E4%7D%3D%5Cleft%7C%5Cdfrac32a%5E2b%5E3c%5E4%5Cright%7C)
Why the absolute value? It's for the same reason that
since both 
and 
return the same number , and 
captures both possibilities. From here, we have
The absolute values disappear on all but the 
term because all of 
, 
and 
are positive, while 
could potentially be negative. So we end up with
<u>m= -19/1</u>
We need to use the slope equation
We are working with the points,
(17, 2) and (18, -17)
x1 y1 x2 y2
<u>m= -19/1</u>
