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Romashka-Z-Leto [24]
3 years ago
13

I need help pls..........

Mathematics
1 answer:
zzz [600]3 years ago
7 0

Answer:

a 14.3

Step-by-step explanation:

23 divided by 4 is 14.3

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Solve:m+ 2/3=1/2 <br><br> A. 1 1/6<br><br> B. 1/6<br><br> C.-1<br><br> D. - 1/6
natita [175]

Answer:

D. - 1/6

Step-by-step explanation:

M + 2/3 = 1/2

M = 1/2 - 2/3

\frac{1}{2} - \frac{2}{3} = \frac{3}{6} -  \frac{4}{6} = -\frac{1}{6}

6 0
3 years ago
Read 2 more answers
Hey guys this is really in hard what is 1-5=
Amiraneli [1.4K]

Answer:

-4

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
What is 14x14x14 equal
N76 [4]
2744 is the answer. can be written as 14^3 just in case you need to know that.
8 0
3 years ago
PLEASE HELP ASAP!!
BabaBlast [244]

Answer:

The first term of the sequence is -120.

Step-by-step explanation:

The formula for the "nth" term of a geometric sequence is shown below:

an = a0*r^(n-1)

Where an is the nth term, r is the ratio and n is the position of the term on the sequence. For this problem we want to find what is the initial term, a0, so we will isolate it in the formula as shown below:

a0*r^(n-1) = an

a0 = an/[r^(n-1)]

We then apply the data given to us

a0 = 31.45728/[-0.8^(7-1)]

a0 = 31.45728/[-0.8^6] =31.45728 /-0.262144= -120

The first term of the sequence is -120.

4 0
3 years ago
Consider a value to be significantly low if its z score less than or equal to minus−2 or consider a value to be significantly hi
ziro4ka [17]

Answer:

If the weight is higher than 5.8886 gr would be considered significantly high

If the weight is lower than 5.6121 gr would be considered significantly low

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:

X \sim N(5.75241,0.06281)  

Where \mu=5.75241 and \sigma=0.06281

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

For the case when z =-2 we can do this:

-2 = \frac{X-5.75241}{0.06281}

And if we solve for X we got:

X = 5.75241 -2*0.06281 =5.6121

And for the other case when Z=2 we have:

2 = \frac{X-5.75241}{0.06281}

And if we solve for X we got:

X = 5.75241 +2*0.06281 =5.8886

If the weight is higher than 5.8886 gr would be considered significantly high

If the weight is lower than 5.6121 gr would be considered significantly low

5 0
3 years ago
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