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never [62]
2 years ago
14

Marsha created this scale drawing of a soccer field, using a scale factor of 1 inch: 12 yards. She wants to make another scale m

odel of the same soccer field, using a scale factor of 1 inch: 36 yards. Find the length and width of the new scale drawing. a 1.33 inches, 2 inches. b 3 inches, 2 inches c 4 inches, 6 inches d 27 inches, 18 inches

Mathematics
2 answers:
s2008m [1.1K]2 years ago
6 0
I would need the see the scale drawing of the original soccer field to answer this question. but you should just divide the original dimensions by 3. 
omeli [17]2 years ago
3 0

Answer:

b 3 inches, 2 inches

Step-by-step explanation:

In the figure attached, the complete question is shown.

Originally the scale is 1 inch: 12 yards, the width is 6 inches, that is, 6*12 = 72 yards, and the length is 9 yards, that is, 9*12 = 108 yards

If the scale is 1 inch: 36 yards, then 72 yards are:

1 inch / x inches = 36 yards / 72 yards

x = 72/36 = 2 inches

which represents the new width.

And 108 yards are:

1 inch / x inches = 36 yards / 108 yards

x = 108/36 = 3 inches

which represents the new length.

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5 0
3 years ago
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A tub is filled with 18000 cm3 of water. It loses one-tenth of its water every 12 hours. What volume of water would be remaining
Lina20 [59]

Answer:

0 cm³

Step-by-step explanation:

the lost of water =

(5×24)/12 x 1/10 × 18000

= 10/10 × 18000 = 18,000 cm³

so, the remaining water in the tub=

18,000 - 18,000 = 0 cm³

(the tub is empty)

6 0
3 years ago
Write the given roots to quadraatic equation
german

Answer:

It's like solving a quadratic, but in reverse, and in this case you'll arrive at x2+x−12=0

Explanation:

We're going to go "backwards" with this problem - normally we're asked to take a quadratic equation and find the roots. So we'll do what we normally do, but in reverse:

Let's start with the roots:

x=3, x=−4

So let's move the constants over with the x terms to have equations equal to 0:

x−3=0, x+4=0

Now we can set up the equation, as:

(x−3)(x+4)=0

We can now distribute out the 2 quantities:

x2+x−12=0

6 0
3 years ago
[Algebra 2] Find the quotient with the necessary restrictions.​
Tatiana [17]

Answer:

The correct answer is:   3x² (4x - 1) / (x - 4) (x - 3) ∧ restriction x ≠ 3, x ≠ 4, x ≠ 0 and x ≠ 1/4

Step-by-step explanation:

Given:

((16x² - 8x + 1) / (x² - 7x + 12)) : ((20x² - 5x) / 15x³) =

dividing with one fraction is the same as multiplying with its reciprocal value

((16x² - 8x + 1) / (x² - 7x + 12)) · (15x³ / (20x² - 5x))

First we need to factorize both numerators and denominators

16x² - 8x + 1 = (4x - 1)²   This is square binomial

x² - 7x + 12 = x² - 4x - 3x + 12 = x (x - 4) - 3 (x - 4) = (x - 4) ( x - 3)

20x² - 5x = 5x (4x - 1)

(4x - 1)² / (x - 4) (x - 3) ·  15x³ / 5x (4x - 1)

The existence of this rational algebraic expression is possible only if it is:

x - 4 ≠ 0 and x - 3 ≠ 0 and x ≠ 0 and 4x - 1 ≠ 0  =>

x ≠ 4 and x ≠ 3 and x ≠ 0 and x ≠ 1/4  This is restriction

Finally we have:

3 x² (4x - 1) / (x - 4) (x - 3)

God with you!!!

8 0
3 years ago
(x+3)^2 and x^2+9 is equivalent?
chubhunter [2.5K]
They are not equivalent, try adding in numerical values for x, both do not come out the same.
3 0
3 years ago
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