Marsha created this scale drawing of a soccer field, using a scale factor of 1 inch: 12 yards. She wants to make another scale m
odel of the same soccer field, using a scale factor of 1 inch: 36 yards. Find the length and width of the new scale drawing. a 1.33 inches, 2 inches. b 3 inches, 2 inches c 4 inches, 6 inches d 27 inches, 18 inches
2 answers:
Answer:
b 3 inches, 2 inches
Step-by-step explanation:
In the figure attached, the complete question is shown.
Originally the scale is 1 inch: 12 yards, the width is 6 inches, that is, 6*12 = 72 yards, and the length is 9 yards, that is, 9*12 = 108 yards
If the scale is 1 inch: 36 yards, then 72 yards are:
1 inch / x inches = 36 yards / 72 yards
x = 72/36 = 2 inches
which represents the new width.
And 108 yards are:
1 inch / x inches = 36 yards / 108 yards
x = 108/36 = 3 inches
which represents the new length.
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Answer:
(1,8) and (-3,0)
Step-by-step explanation:
We simply graph the two functions in the same graph. The solution set to the system is given by the points where the two functions intersect. For this case, the two functions intersect at;
(1,8) and (-3,0)
The solution set is thus; (1,8) and (-3,0)
Check the attachment below;
Answer:
(a) even function
(b) odd function
Step-by-step explanation:
From the given information;
Any function x(t) can be said to be the sum of even and odd functions.
i.e.
where;
x(t) is a real function.
For a real and even function, the Fourier transform is also real and even.
Also, the Fourier Transform of a real and odd function is imaginary and odd.
The behavior of X(f) largely depends on the behavior of x(t).
If x(t) is real and even, then x(f) is real and even valued function
Thus, the real part of X(f) is an even function.
If x(t) is real and odd, then x(f) is imaginary and odd valued function
Thus, the imaginary part of X(f) is an odd function.