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Sergio [31]
2 years ago
6

Benny earns $12.00 per hour as a lifeguard. He earns a bonus of $75.00 for taking a training course. Which graph best represents

the number of hours must be work to earn at least $399.00?

Mathematics
2 answers:
Cerrena [4.2K]2 years ago
8 0
Yea definitely C since its greater than 27
Scorpion4ik [409]2 years ago
7 0

Answer:

C.

Step-by-step explanation:

At least means greater than or equal to.

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4% of _____ days is 56 days
schepotkina [342]
We have an equation: 56/? = 4/100

Cross multiply:
4*? = 56*100
⇒ ? = 56*100/4
⇒ ?= 1,400

4% of 1,400 days is 56 days~
4 0
3 years ago
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Simplify negative 2 and 1 over 6 − negative 7 and 1 over 3. Please help!
kvv77 [185]
They are simplified. 2 1/6 cannopt be simplified neither can 7 1/3 

Brainliest please i need one more before im expert

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3 years ago
The difference of 5 times the cube of x cubed and<br> the quotient of 4 times x and 3
Anvisha [2.4K]

Answer:

I don't know what you are looking for, but I am going with (15x^3 - 4x)/3

Step-by-step explanation:

5x^3 - 4x/3

5x^3/1 - 4x/3

15x^3/3 - 4x/3

(15x^3 - 4x)/3

3 0
3 years ago
What is the value of x?
Hitman42 [59]

Answer:

Step-by-step explanation:

Since RQT=155

4x-20+3x+14=155

7x-6=155

7x=161

x=23

3 0
3 years ago
Read 2 more answers
A group of 54 college students from a certain liberal arts college were randomly sampled and asked about the number of alcoholic
Ket [755]

Answer:

t=\frac{5.25-4.73}{\frac{3.98}{\sqrt{54}}}=0.9601  

P-value  

First we find the degrees of freedom given by:

df = n-1= 54-1=53

Since is a two-sided test the p value would be:  

p_v =2*P(t_{53}>0.9601)=0.3414  

Step-by-step explanation:

Data given and notation  

\bar X=5.25 represent the sample mean

s=3.98 represent the sample standard deviation

n=54 sample size  

\mu_o =4.73 represent the value that we want to test  

\alpha represent the significance level for the hypothesis test.  

z would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the mean differs from 4.73, the system of hypothesis would be:  

Null hypothesis:\mu =4.73  

Alternative hypothesis:\mu \neq 4.73  

Since we know don't the population deviation, is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic  

We can replace in formula (1) the info given like this:  

t=\frac{5.25-4.73}{\frac{3.98}{\sqrt{54}}}=0.9601  

P-value  

First we find the degrees of freedom given by:

df = n-1= 54-1=53

Since is a two-sided test the p value would be:  

p_v =2*P(t_{53}>0.9601)=0.3414  

7 0
3 years ago
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