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FrozenT [24]
3 years ago
10

When think of a number double it and add five and get 13 What the number I Thought

Mathematics
1 answer:
aev [14]3 years ago
3 0

Let the no be x

ATQ

\\ \sf\longmapsto 2x+5=13

\\ \sf\longmapsto 2x=13-5

\\ \sf\longmapsto 2x=8

\\ \sf\longmapsto x=\dfrac{8}{2}

\\ \sf\longmapsto x=4

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How do you solve a question algbraically
Julli [10]

Answer:

Step 1: Multiply the entire first equation by 2.

Step 2: Rewrite the system of equations, replacing the first equation with the new equation.

Step 3: Add the equations.

Step 4: Solve for x.

Step 5: Find the y-value by substituting in 3 for x in either equation.

Step 6: Identify the solution as an ordered pair.

3 0
3 years ago
2. Sketch the graph: 4y – 3x = 12.​
goblinko [34]

Answer:

  see below

Step-by-step explanation:

A graphing calculator is useful for this.

__

To find the x-intercept, set y=0 and solve for x:

  0 -3x = 12

  x = -4 . . . . . . divide by -3

To find the y-intercept, set x=0 and solve for y:

  4y - 0 = 12

  y = 3 . . . . . . divide by 4

Plot the x- and y-intercepts on their respective axes and draw a line through them.

4 0
3 years ago
99 POINT QUESTION, PLUS BRAINLIEST!!!
Elden [556K]
We draw region ABC. Lines that connect y = 0 and y = x³ are vertical so:
(i) prependicular to the axis x - disc method;
(ii) parallel to the axis y - shell method;
(iii) parallel to the line x = 18 - shell method.

Limits of integration for x are easy x₁ = 0 and x₂ = 9.
Now, we have all information, so we could calculate volume.

(i)

V=\pi\cdot\int\limits_a^bf^2(x)\, dx\qquad\implies \qquad a=0\qquad b=9\qquad f(x)=x^3


V=\pi\cdot\int\limits_0^9(x^3)^2\, dx=\pi\cdot\int\limits_0^9x^6\, dx=\pi\cdot\left[\dfrac{x^7}{7}\right]_0^9=\pi\cdot\left(\dfrac{9^7}{7}-\dfrac{0^7}{7}\right)=\dfrac{9^7}{7}\pi=\\\\\\=\boxed{\dfrac{4782969}{7}\pi}

Answer B. or D.

(ii)

V=2\pi\cdot\int\limits_a^bx\cdot f(x)\, dx


V=2\pi\cdot\int\limits_0^{9}(x\cdot x^3)\, dx=2\pi\cdot\int\limits_0^{9}x^4\, dx=
2\pi\cdot\left[\dfrac{x^5}{5}\right]_0^9=2\pi\cdot\left(\dfrac{9^5}{5}-\dfrac{0^5}{5}\right)=\\\\\\=2\pi\cdot\dfrac{9^5}{5}=\boxed{\dfrac{118098}{5}\pi}

So we know that the correct answer is D.

(iii)
Line x = h

V=2\pi\cdot\int\limits_a^b(h-x)\cdot f(x)\, dx\qquad\implies\qquad h=18


V=2\pi\cdot\int\limits_0^9\big((18-x)\cdot x^3\big)\, dx=2\pi\cdot\int\limits_0^9(18x^3-x^4)\, dx=\\\\\\=2\pi\cdot\left(\int\limits_0^918x^3\, dx-\int\limits_0^9x^4\, dx\right)=2\pi\cdot\left(18\int\limits_0^9x^3\, dx-\int\limits_0^9x^4\, dx\right)=\\\\\\=2\pi\cdot\left(18\left[\dfrac{x^4}{4}\right]_0^9-\left[\dfrac{x^5}{5}\right]_0^9\right)=2\pi\cdot\Biggl(18\biggl(\dfrac{9^4}{4}-\dfrac{0^4}{4}\biggr)-\biggl(\dfrac{9^5}{5}-\dfrac{0^5}{5}\biggr)\Biggr)=\\\\\\

=2\pi\cdot\left(18\cdot\dfrac{9^4}{4}-\dfrac{9^5}{5}\right)=2\pi\cdot\dfrac{177147}{10}=\boxed{\dfrac{177147\pi}{5}}

Answer D. just as before.

6 0
3 years ago
Using the formula C = 2, find the circumference of a circle with diameter of 20 inches. Round your answer to the nearest inch
Svetllana [295]

Answer:

The circumference is approximately 314 inches.

Step-by-step explanation:

3.14 x r^2

3.14 x 10^2

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Circumference: 314

8 0
3 years ago
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There must be more than 10 visitors registered for the guided hike in order for it to be offered. Otherwise, the hike will be ca
Semmy [17]
I think that this is correct but the question was a little confusing, V > 10.
If I am wrong sorry in advance.
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