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chubhunter [2.5K]
3 years ago
14

Help please, my computer is slow please wait a sec.

Mathematics
2 answers:
Dahasolnce [82]3 years ago
4 0
The answer is 339.12
harina [27]3 years ago
3 0
Among the more frustrating issues of Windows 8/8.1, the “Please Wait<span> Screen” error is markedly  Method 2: </span>Repair<span> system files using SFC scan. This is a  This process is considered to conflict with the </span>computer's<span> operations and bring it to freeze at the startup screen.  When you see this count 1 and 2 (not exactly 2 </span>sec<span>.</span>
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What is the product of 5 and 2/3
alukav5142 [94]
The product of 5 and 2/3 is 5.6666
5 0
3 years ago
Read 2 more answers
Can people help me on this please I need it!!! It’s really important
Firdavs [7]

Answer:

62

Step-by-step explanation:

The total of a triangle is 180

so 78+48 is 118

180-118=62

5 0
3 years ago
Find the first 5 terms of the arithmetic sequence : a(1)=-3 , a(17)=-20
madreJ [45]
The explicit formula for arithmetic sequence is:
an=a+(n-1)d
where:
a=first term
d=common difference 
given:
a3=22
a(17)=-20
substituting this in our equation we get:
22=a+(3-1)d
22=a+2d
a=22-2d........i

also:
-20=a+(17-1)d
-20=a+16d.....ii
but substituting i in ii we get:
-20=22-2d+16d
-20-22=14d
-42=14d
d=-3
but:
a=22-2d
a=22-2(-3)
a=28
thus the formula will be:
an=28-3(n-1)
thus the first term will be 28
the 2nd term will be:
a2=28-3(2-1)
a2=25

the 3rd term will be:
a3=28-3(3-1)
a3=28-6
a3=22

a4=28-3(4-1)
a4=28-9
a4=15

a5=28-3(5-1)
a5=28-3(4)
a5=28-12
a5=15

5 0
3 years ago
Solve the following linear equation for k.<br> 2 (k-5) + 3k = k + 6
kiruha [24]

Answer:

2(k-5)+3k=k+6

-3k. -3k

2(k-5)=-2k+6

/2. /2

k-5=-k+3

+k. +k

2k-5=3

+5. +5

2k=8

/2. /2

k=4

7 0
3 years ago
If RT = 6 and RS = 9, then RX =<br> A - sqrt(54)<br> B - 13.5<br> C - 7.2<br> D - 4
wolverine [178]

Answer:

Option D RX=4 units

Step-by-step explanation:

we know that

<em>In the right triangle RTS</em>

The cosine of angle TRS is equal to

cos(TRS)=RT/RS

substitute

cos(TRS)=6/9 -----> equation A

<em>In the right triangle RTX</em>

The cosine of angle TRX is equal to

cos(TRX)=RX/RT

substitute

cos(TRX)=RX/6 -----> equation B

∠TRS=∠TRX -----> is the same angle

Match equation A and equation B

6/9=RX/6

RX=6*6/9=4 units

5 0
3 years ago
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