14 20
---- = ----- cross multiply
3x x-5
14(x-5) = 3x (20)
14x - 70 = 60x
-14x -14x
-70 = 36x
/36 /36
-70/36 = x
or
-35/18 = x
132/2 = 66
66/2 = 33
33/3 = 11
11/11 = 1
132 = 2^2 * 3 * 11
55121/11 = 5011
5011/5011 = 1
55,121 = 11 * 5011
LCM = common factor with larger exponent * not common factors
LCM = 2^2 * 3 * 11 * 5011
LCM = 661,452
The expected length of code for one encoded symbol is

where
is the probability of picking the letter
, and
is the length of code needed to encode
.
is given to us, and we have

so that we expect a contribution of

bits to the code per encoded letter. For a string of length
, we would then expect
.
By definition of variance, we have
![\mathrm{Var}[L]=E\left[(L-E[L])^2\right]=E[L^2]-E[L]^2](https://tex.z-dn.net/?f=%5Cmathrm%7BVar%7D%5BL%5D%3DE%5Cleft%5B%28L-E%5BL%5D%29%5E2%5Cright%5D%3DE%5BL%5E2%5D-E%5BL%5D%5E2)
For a string consisting of one letter, we have

so that the variance for the length such a string is

"squared" bits per encoded letter. For a string of length
, we would get
.
Answer:
g(x) = sin(x)
f(x) = e^x
Step-by-step explanation:
Answer:
Police officers, whether plain-clothed or uniformed, carry a variety of equipment with them on service calls. Police in uniform carry much more equipment than those in plain clothes, and members of special operations teams, such as SWAT and crowd-control units, carry even more, sometimes including full body armour complete with helmet, leg pads, and shield.
Step-by-step explanation:
hope it helped!
p.s it would be cool it you would give me brainliest