The probability of obtaining a grid that does not have a 2-by-2 red square 16 2/3%
probability : The probability of an event can be calculated by means of probability formula via honestly dividing the favorable quantity of outcomes by way of the total variety of viable consequences.
<u>Step-by using-step clarification:</u>
<u>given that:</u>
form are both square or circle with both equally likely :
for this reason,
P(square) = half of ; P(circle) = half of
color are either blue, pink or inexperienced with the 3 equally likely ;
P(purple) = 1/3 ; P(green) = 1/three ; P(blue) = 1/three
chance of creating a inexperienced circle :
independent probability
P(green n circle) = p(inexperienced) * p(circle)
P(green n circle) = 1/3 * half of
P(green n circle) = 1/6
= 0.16666
(0.16666 * 100%) = 16.6666%
= 16 2/3%
To learn more about probability Visit : brainly.com/question/18920335
#SPJ4
Answer:
ummmmm if im not wrong 34
Step-by-step explanation:
Answer:
Step-by-step explanation:
The altitude to the hypotenuse of a right triangle create two smaller triangles, all of which are similar to the original. This means corresponding sides are proportional.
3. Using the above relationship, ...
short-side/hypotenuse = 8/y = y/(8+23)
y^2 = 8·31
y = 2√62
__
long-side/hypotenuse = z/(8+23) = 23/z
z^2 = 23·31
z = √713
__
short-side/long-side = 8/x = x/23
x^2 = 8·23
x = 2√46
_____
4. The picture is fuzzy, but we think the lengths are 25 and 5. If they're something else, use the appropriate numbers. Using the same relations we used for problem 3,
y = √(5·25) = 5√5 . . . . . . . = √(short segment × hypotenuse)
z = √(20·25) = 10√5 . . . . . = √(long segment × hypotenuse)
x = √(5·20) = 10 . . . . . . . . . = √(short segment × long segment)
Answer:
Step-by-step explanation:
3x3
60 hope it helps and its right
