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Gwar [14]
3 years ago
13

Given a:b and b:c, find a:b:c. Write the ratio in simplest form. a:b=6:10 and b:c=21:33

Mathematics
1 answer:
kherson [118]3 years ago
7 0

Answer:

a:b = 6:10 = 3:5 = 21:35

b:c = 21:33 = 7:11 = 35:55

a:b:c = 21:35:55

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Create an equivalent expression that includes a set of parentheses that make the value of the expression 13. Remember, you can h
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Answer:

(2*9)-5+0

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What is the value of x in the equation 1.5(x + 4) – 3 = 4.5(x – 2)
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Step-by-step explanation:

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What is the value of x? There is isosceles triangle. The measure of angle which is between two congruent sides is (6x+10⁰). The
max2010maxim [7]
<h3><u>Answer</u><u>:</u><u>-</u></h3>

x=17

<h3><u>step-by</u><u>-</u><u>step</u><u> </u><u>Explanation</u><u>:</u><u>-</u></h3>

{\boxed{\quad\:\mapsto\rm Firstly\:Let's\:understand\:the\:concept:-}}

<h3 />

This is a isosceles triangle. As it is a triangle we can apply sum theory. we have to take the sum of given unknown polynomials as 180° .Then by solving it we can find the value of x.

<h3><u>Solution</u><u>:</u><u>-</u></h3>

Given angles

  • (6x+10°)
  • (x+17°)
  • (4x-34)°

According to sum theory

{\boxed{\sf The \:sum\:of\:angles=180°}}

  • Substitute the values

\qquad \quad{:}\longmapsto\tt (6x+10)+(x+17)+(4x-34)=180

  • Remove brackets

\qquad \quad{:}\longmapsto\tt 6x+10+x+17+4x-34=180

  • Together like polynomials and constants

\qquad \quad{:}\longmapsto\tt 6x+x+4x+10+17-34=180

\qquad \quad{:}\longmapsto\tt 11x-7=180

  • Interchange sides

\qquad \quad{:}\longmapsto\tt 11x=180+7

\qquad \quad{:}\longmapsto\tt 11x=187

\qquad \quad{:}\longmapsto\tt x=\cancel{\dfrac{187}{11}}

  • Simplify

\qquad \quad{:}\longmapsto\tt x=17

\therefore\sf The \:value\:of\:x\;is\:17.

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