What method would you choose to solve the equation? 4x^2-48=0

Mathematics

1 answer:

melamori03 [73]3 years ago

6 0

I'd definitely factor 4x^2-48 first. Factors are (4)(x^2-12).

This factors further: (4)* (x-2sqrt(3) ) * (x+2sqrt(3) )

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