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Anit [1.1K]
3 years ago
13

What method would you choose to solve the equation? 4x^2-48=0

Mathematics
1 answer:
melamori03 [73]3 years ago
6 0
I'd definitely factor 4x^2-48 first.  Factors are (4)(x^2-12).

This factors further:                                         (4)* (x-2sqrt(3) ) * (x+2sqrt(3) )
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Choose the expression for 9 decreased by 9
Makovka662 [10]

Answer:

Mathematically speaking, it is 9 - 9

5 0
2 years ago
Find the exact value of cos(a+b) if cos a=-1/3 and cos b=-1/4 if the terminal side if a lies in quadrant 3 and the terminal side
maria [59]

Answer:

cos(a + b) = \frac{1}{12}(1-2\sqrt{30})

Step-by-step explanation:

cos(a + b) = cos(a).cos(b) - sin(a).sin(b) [Identity]

cos(a) = -\frac{1}{3}

cos(b) = -\frac{1}{4}

Since, terminal side of angle 'a' lies in quadrant 3, sine of angle 'a' will be negative.

sin(a) = -\sqrt{1-(-\frac{1}{3})^2} [Since, sin(a) = \sqrt{(1-\text{cos}^2a)}]

         = -\sqrt{\frac{8}{9}}

         = -\frac{2\sqrt{2}}{3}

Similarly, terminal side of angle 'b' lies in quadrant 2, sine of angle 'b' will be  negative.

sin(b) = -\sqrt{1-(-\frac{1}{4})^2}

         = -\sqrt{\frac{15}{16}}

         = -\frac{\sqrt{15}}{4}

By substituting these values in the identity,

cos(a + b) = (-\frac{1}{3})(-\frac{1}{4})-(-\frac{2\sqrt{2}}{3})(-\frac{\sqrt{15}}{4})

                = \frac{1}{12}-\frac{\sqrt{120}}{12}

                = \frac{1}{12}(1-\sqrt{120})

                = \frac{1}{12}(1-2\sqrt{30})

Therefore, cos(a + b) = \frac{1}{12}(1-2\sqrt{30})

5 0
3 years ago
(5 - 7i)(8 + i)
docker41 [41]

Answer:

(5 - 7i)(8 + i)

F) 40 - 561

H) 37 - 371

K) -16 - 2i

G) -33 - 61i

J) 47 - 51i

- 9 below

Step-by-step explanation:

7 0
2 years ago
Gentry poured 23.5 ounces of milk and 7.75 ounces of cream in a mixing bowl.
denpristay [2]
Notice that because the capacity of the bowl is 35.5 ounces, but there has already been 31.25 ounces total added to it (23.5 ounces + 7.75 ounces), all that needs to be done is subtract 31.25 from 35.5:
35.5 - 31.25 = 4.25 ounces of cream could be added
4 0
3 years ago
a solid consists of cylinder surmounted by a right circular cone. The height of the cone is 2h. If the volume of the solid is 3
Mademuasel [1]

Answer:

height of cylinder = 4/3 h

Step-by-step explanation:

The solid has a cylinder surmounted with a cone .Therefore, the volume of the solid is the sum of the cone and the cylinder.

volume of the solid = volume of cylinder + volume of cone

volume of the solid = πr²h + 1/3πr²h

let

height of the cylinder = H

recall

the height of the cone = 2h

volume of the solid = πr²h + 1/3πr²h

3(1/3πr²2h) = πr²H + 1/3πr²2h

2πr²h = πr²H + 2/3 πr²h

πr²(2h) = πr²(H + 2/3 h)

divide both sides by πr²

2h = H + 2/3 h

2h - 2/3h = H

H = 6h - 2h/3

H = 4/3 h

height of cylinder = 4/3 h

8 0
3 years ago
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