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bonufazy [111]
4 years ago
5

A bird is flying at a height of 2 meters above the sea level. The angle of depression from the bird to the fish it sees on the s

urface of the ocean is 15∘. Find the distance the bird must fly to be directly above the fish. Round to the nearest ten

Mathematics
1 answer:
miskamm [114]4 years ago
7 0

See the attached picture:

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In a different plan forarea codes the first digit is 1 through 6 the second digit is either 5 6 7 or 8 the third digit could be
EastWind [94]

Answer:

216

Step-by-step explanation:

There are 6 options for the first digit.

There are 4 options for the second digit.

There are 9 options for the third digit.

The total number of combinations is 6 × 4 × 9 = 216.

7 0
3 years ago
The number model may be used to simplify which of the following
shutvik [7]

The answer is A, I think

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3 years ago
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pirate ordered twice as many blankets as she did quilts from the Department Store where she works the order was 126 items how ma
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She ordered 42 quilts and 84 blankets
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3 years ago
A company with a fleet of 150 cars found that the emissions systems of only 4 out of the 25 they tested failed to meet pollution
salantis [7]

Answer:

No, there is no strong evidence that the percentage of the fleet out of compliance is different from their initial thought.

Step-by-step explanation:

We are given that a company with a fleet of 150 cars found that the emissions systems of only 4 out of the 25 they tested failed to meet pollution control guidelines.

The company initially believed that 30% of the fleet was out of compliance.

<u><em>Let p = percentage of the fleet that was out of compliance.</em></u>

SO, Null Hypothesis, H_0 : p = 30%   {means that the percentage of the fleet out of compliance is same as their initial thought}

Alternate Hypothesis, H_A : p \neq 30%   {means that the percentage of the fleet out of compliance is different from their initial thought}

The test statistics that will be used here is <u>One-sample z proportion</u> <u>statistics</u>;

                                 T.S.  = \frac{\hat p-p}{{\sqrt{\frac{\hat p(1-\hat p)}{n} } } } }  ~ N(0,1)

where, \hat p = percentage of the fleet out of compliance = \frac{4}{25} = 16%

           n = sample of systems tested = 25

So, <u><em>test statistics</em></u>  =  \frac{0.16-0.30}{{\sqrt{\frac{0.16(1-0.16)}{25} } } } }

                              =  -1.909

The value of the test statistics is -1.909.

<em>Since in the question we are not given with the level of significance at which hypothesis can be tested, so we assume it to be 5%. Now at 5% significance level, </em><u><em>the z table gives critical values between -1.96 and 1.96 for two-tailed test.</em></u><em> </em>

<em>Since our test statistics lies within the range of critical values of z, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.</em>

Therefore, we conclude that the percentage of the fleet out of compliance is same as their initial thought.

3 0
3 years ago
Please help and don't just put a random answer to steal my points
Valentin [98]

Answer:

C)  f(n) = 5n-1

Step-by-step explanation:

5 0
3 years ago
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