Answer:
The coordinates of the other end is 
Step-by-step explanation:
Given


Required
Find the coordinates of the other end
Let Midpoint be represented by (x,y);
(x,y) = (5,2) is calculated as thus

So
and 
Where
and 
So, we're solving for 
Solving for 
Substitute 5 for x and -6 for x₁

Multiply both sides by 2


Add 6 to both sides


Solving for 

Substitute 2 for y and 2 for y₁

Multiply both sides by 2


Subtract 2 from both sides



Hence, the coordinates of the other end is 
The completely factored form of the provided polynomial is (p -2) (p+ 2) (p² +4). The option 4 is the correct option.
<h3>What is polynomial?</h3>
Polynomial equations is the expression in which the highest power of the unknown variable is n (n is a real number).
The polynomial equation given in the problem is,

Let the factor form of the polynomial is f(p). Thus,

Using the formula of difference of squares, we get,

Thus, the completely factored form of the provided polynomial is (p -2) (p+ 2) (p² +4). The option 4 is the correct option.
Learn more about polynomial here;
brainly.com/question/24380382
The true statements about the triangles RST and DEF are: (a), (d) and (e)
<h3>How to determine the true statements?</h3>
The statement ΔRST ≅ ΔDEF means that the triangles RST and DEF are congruent.
This above implies that:
- The triangles can be mapped onto each other by rigid transformations such as reflection, translation and rotation
- The transformation does not include dilation
- Corresponding sides are congruent
The above means that the possible true statements are: (a), (d) and (e)
Read more about transformation at:
brainly.com/question/4289712
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A few ways. you can enter it into a calculator for one, but the easiest way would be to reference a unit circle and look for an ordered pair where sin (the y value), is equal to -1/2
on a unit circle, the sin value is -1/2 at 7pi/6 and 11pi/6
because sin is the y value, it will additionally be in the quadrants III or IV based on the fact that (-1/2) as a sin value IS a negative and would have to be found in a quadrant in which sin is negative (the lower half of a coordinate plane, in this case)