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grigory [225]
3 years ago
12

The surface area of a rectangular prism is the sum of:

Mathematics
1 answer:
Anastaziya [24]3 years ago
8 0

Answer:

Surface area of prism=2(l+w)h+2(lw)

Step-by-step explanation:

We are given that surface area of rectangular prism=2(lw+lh+wh)

We have to write an expression that represents the surface area of prism.

Base of prism is made from length and width

Perimeter of base =2(l+w)

Area of base=lw=Area of top

Surface area of prism=Perimeter of base multiply by height+2 area of base

Because area of base and area of top are equal.

Surface area of prism=Ph+2B=2(l+w)h+2(lw)

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Given: In triangle ABC , AD is drawn perpendicular to BC.

Since AD is drawn perpendicular to BC, it creates two right triangles: ADB and ADC.

Prove that: AB^2-BD^2 = AC^2-CD^2

Pythagoras triangle for right angle, the square of the length of the hypotenuse is equal to the sum of the squares of the lengths of the legs.

In a right angle triangle ADB;

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or

AD^2= AB^2-BD^2                      .......[1]

Now, in right angle triangle ADC;

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or we can write this as;

AD^2= AC^2-CD^2                    ......[2]

Substituting the equation [1] in [2] we get;

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student 2 did

hope this helps

since it is only addition and subtraction, you can mix the orders up, as long as you use the correct sign
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