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grigory [225]
3 years ago
12

The surface area of a rectangular prism is the sum of:

Mathematics
1 answer:
Anastaziya [24]3 years ago
8 0

Answer:

Surface area of prism=2(l+w)h+2(lw)

Step-by-step explanation:

We are given that surface area of rectangular prism=2(lw+lh+wh)

We have to write an expression that represents the surface area of prism.

Base of prism is made from length and width

Perimeter of base =2(l+w)

Area of base=lw=Area of top

Surface area of prism=Perimeter of base multiply by height+2 area of base

Because area of base and area of top are equal.

Surface area of prism=Ph+2B=2(l+w)h+2(lw)

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Lines d, e, and f are parallel. That means they have the same slope. Each of these lines has a slope of −3. Enter numbers to com
Sloan [31]

Answer:

Line d : y = -3x - 3

Line e : y = -3x - 2

Line f  : y= -3x + 2

Step-by-step explanation:

Given that,

The slope of each line is -3.

Now,

We know that,

Equation of line is represented by y = mx + c

where m is the slope and c is the y-intercept.

Now,

Given that,

Line d goes through (0, - 3) and (- 1, 0).

So,

y-intercept of Line d is -3

∴ we get

Equation of Line d is : y = -3x -3

Now,

Given that,

Line e goes through (-1, 2) and (0, -2).

So,

y-intercept of Line e is -2

∴ we get

Equation of Line e is : y = -3x - 2

Now,

Given that,

Line f goes through (0, 2) and (1, -1).

So,

y-intercept of Line e is 2

∴ we get

Equation of Line f is : y = -3x + 2

6 0
3 years ago
10x^3/5x^2 2/x. 2x 2 x/2
Troyanec [42]
-5x•(2x^2+x+3) is the answer
8 0
3 years ago
HELP MEEEE PLEASEEEEEEEEEEEEEE
Agata [3.3K]

Answer:

a = 4

Step-by-step explanation:

a^2 + b^2 = c^2

a= ?

b= 3

c= 5 (c is always the hypotenuse)

*plug in given values

a^2 + 3^2 = 5^2

a^2 + 9 = 25

-9 -9

a^2 = 16

*find the square root

sqrt(a) = sqrt(16)

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8 0
3 years ago
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Mitch is saving money to go on a camping trip this summer. So far he has saved $160 which is 40% of the money needed to go on th
faust18 [17]
I think the answer is D. 
8 0
4 years ago
What is the slope intercept from of the equation of the line that that passes through the points (-3, 2) and (1, 5)
viva [34]

The slope-intercept form of a line:

y=mx+b\\\\m=\dfrac{y_2-y_1}{x_2-x_1}\to slope\\\\b\to y-intercept

We have:

(-3,\ 2)\to x_1=-3,\ y_1=2\\(1,\ 5)\to x_2=1,\ y_2=5

Substitute:

m=\dfrac{5-2}{1-(-3)}=\dfrac{3}{4}

y=\dfrac{3}{4}x+b

Put the values of coordinates of the point (1, 5) to the equation of a line:

5=\dfrac{3}{4}(1)+b\\\\5=\dfrac{3}{4}+b\qquad|-\dfrac{3}{4}\\\\b=4\dfrac{1}{4}

Answer: y=\dfrac{3}{4}x+4\dfrac{1}{4}


5 0
3 years ago
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