Question

E total kinetic energy of a 2500 lbm car when it is moving at 80 mph (in BTU)?

Answer 1

Answer:

KE= 687.21 BTU

Explanation:

Given that

Mass of car = 2500 lbm

We know that 1 lb=0.45 kg

So the mass of car  m =1133.98 kg

Velocity of car= 80 mph

We know that 1 mph =0.44 m/s

So velocity of car = 35.76 m/s

As we know that kinetic energy (KE) is given as follows

$KE=\dfrac{1}{2}mv^2$

Now by putting the values

$KE=\dfrac{1}{2}\times 1133.98\times 35.76^2$

KE=725.05 KJ

We know that   1 KJ = 0.94 BTU

So  KE= 687.21 BTU