Which of the following is an acronym for a recently introduced type of vehicle that has a high fuel economy rating?A.SUVB.AQIC.H
1 answer:
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Answer:
distance = 22.57 ft
superelevation rate = 2%
Explanation:
given data
radius = 2,300-ft
lanes width = 12-ft
no of lane = 2
design speed = 65-mph
solution
we get here sufficient sight distance SSD that is express as
SSD = 1.47 ut + ..............1
here u is speed and t is reaction time i.e 2.5 second and a is here deceleration rate i.e 11.2 ft/s² and g is gravitational force i.e 32.2 ft/s² and G is gradient i.e 0 here
so put here value and we get
SSD = 1.47 × 65 ×2.5 +
solve it we get
SSD = 644 ft
so here minimum distance clear from the inside edge of the inside lane is
Ms = Rv ( 1 - ) .....................2
here Rv is = R - one lane width
Rv = 2300 - 6 = 2294 ft
put value in equation 2 we get
Ms = 2294 ( 1 - )
solve it we get
Ms = 22.57 ft
and
superelevation rate for the curve will be here as
R = ..................3
here f is coefficient of friction that is 0.10
put here value and we get e
2300 =
solve it we get
e = 2%
Answer:
(a) The current in amperes that flows through the toy's circuit is 0.923A
(b) The power supplied to the toy is 5.78721W
(c) The internal resistance r2 of the failed dry cell is 72Ω
Explanation:
From the circuit diagram attached. We have the electric component:
B1 = 3* 1.58 = 4.74V
B2 = 1.53V
r1 = 3*0.0205 = 0.0615Ω
r2 = 0.105Ω
R = 6.625Ω
Since the internal resistances and the resistor R are connected in series, we can calculate the total resistance RT as
RT = r1 + r2 +R = 0.0615 + 0.105 + 6.625
= 6.7915Ω
Total Voltage supplied to the circuit by both batteries V = B1 + B2 = 4.74 + 1.53 = 6.27V
(a) CIRCUIT CURRENT
The current I, flowing through the circuit is i = =
=0.923A
The current in amperes that flows through the toy's circuit is 0.923A
(b) THE POWER SUPPLIED TO THE TOY
Power P = I*V =0.923*6.27 = 5.78721W
The power supplied to the toy is 5.78721W
(c) THE VALUE OF r2
Due to dry cell failure, the power supplied to the toy is reduced to 0.5W
Now Power P = . To calculate the new total resistance of the circuit we will make R the subject of the formular
R= =
=
= 78.6258Ω
Remember that RT = r1 + r2 + R
r1 =RT- (R +r2)
r1 = 78.6258 - 6.6865 =71.9393Ω
The internal resistance r2 of the failed dry cell is 72Ω