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3 years ago

Can be used to eliminate rubbing friction of wheel touching frame. 1.Traction 2.Thrust washer

Engineering

1 answer:

Vilka [71]3 years ago

5 0

Answer:

thrust washer

can be used to eliminate rubbing friction of wheel touching frame

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True or False; If I was trying to find the Voltage of my computer, and I was given the Watts and Amps it uses, I would use Watt'

defon

Answer:

true

Explanation:

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2 years ago

Convert 25 mm into in.

mihalych1998 [28]

Answer:

25 mm = 0.984252 inches

Explanation:

Millimeter and inches are both units of distance. The conversion of millimeter into inches is shown below:

1 mm = 1/25.4 inches

From the question, we have to convert 25 mm into inches

Thus,

25 mm = (1/25.4)*25 inches

So,

$25 mm=\frac{25}{25.4} inches$

Thus, solving we get:

25 mm = 0.984252 inches

4 0

3 years ago

Which of the following is described as a way engineers can test and investigate how things should be under certain circumstances

goblinko [34]

Answer:

The option that is best described as a way engineers can test and investigate how things should be under certain circumstances is;

Modeling

Explanation:

Modeling is a tool an engineer can use for the physical representation of a system that will facilitate the definition, testing and analysis, communication, data generation, data verification and data validation of given concepts

Models also aid in setting specifications, supporting designs, and verification of a given system

Therefore, with modeling engineers can investigate the behavior of systems under given environmental conditions.

3 0

3 years ago

A 3.5-m3 rigid tank initially contains air whose density is 2 kg/m3 . The tank is connected to a high-pressure supply line throu

Mumz [18]

Answer:

Explanation:

First, we find the mass of the air originally in the tank.

Density is given as mass divided by volume. It is given as:

$Density = \frac{mass}{volume}$

Therefore, mass is:

$mass = denisty *volume$

Density of air = $2 kg/m^3$ ; Volume of the tank = $3.5 m^3$

$=> Mass = 3.5 * 2 = 7 kg$

The mass of the air initially in the tank is 7 kg.

After air is allowed to enter, the mass changes.

New density = $6.5 kg/m^3$

The new mass will be:

$Mass = 6.5 * 3.5 = 22.75 kg$

We can now find the mass of air that has entered the tank:

Mass of air that entered tank = New mass of air - Original mass of air

M = 22.75 - 7.0 = 15.75 kg

The mass of air that entered the tank is 15.75 kg.

6 0

3 years ago

What is A roofed structure that is similar to a porch, but is detached from the house.

agasfer [191]

Answer:

a gazebo

Explanation:

6 0

3 years ago

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