3 years ago

what is the lateral area of a square pyramid with a side length of 11.2 centimeters and slant height 20 centimeters

Mathematics

1 answer:

hammer [34]3 years ago

4 0

Lateral sides consiste of 4 congruentisosceles triangle
lateral area

= 4 * 0.5 * 11.2 * 20
= 448 cm^2

You might be interested in

Maria washes the windows in her house every 2 tweaks, meows her lawn every 3 weeks, and trims her garden bushes every 5 weeks. T

oee [108]

In another 30 weeks, because 2x3x5=30 weeks where she does all of the activities.

4 0

3 years ago

Harold has four classes each school morning each class is an hour long and there is 10 minutes between classes the first class s

Y_Kistochka [10]

The 4th class ends at 12:40

3 0

2 years ago

PLEASE HELP!! NO LINKS!!

dlinn [17]

Answer:

42.1 cm

Step-by-step explanation:

θ = 265°

Radius (r) = 9.1 cm

Arc length of major arc GH = θ/360 × 2πr

Plug in the values into the equation

Length of arc GH = 265/360 × 2 × π × 9.1

= 42.0886149

= 42.1 cm (nearest tenth)

6 0

2 years ago

Add. −38+(−2910) Enter your answer as a simplified fraction by filling in the boxes.

Bumek [7]

Answer:

-2948

Step-by-step explanation:

the only fraction it can be is -2948/1 but it is the same thing as the answer itself

4 0

2 years ago

Point m is the midpoint of kL. M(1,-1) and L(8,-7. What are the coordinates of point k?

Phoenix [80]

Answer: (-6, 5)

Step-by-step explanation:

Use the Midpoint Formula: $\dfrac{(x_k, y_k)+(x_L,y_L)}{2}=(x_m, y_m)$

Separate the x's and y's and solve them individually:

$\dfrac{x_k+x_L}{2}=x_m\qquad \qquad \qquad \qquad\dfrac{y_k+y_L}{2}=y_m\\\\\\\dfrac{x_k+8}{2}=1\qquad \qquad \qquad \qquad \qquad \dfrac{y_k-7}{2}=-1\\\\\\x_k+8=2\qquad \qquad \qquad \qquad \qquad y_k-7=-2\\\\\\x_k\quad =-6 \qquad \qquad \qquad \qquad \qquad y_k\qquad =5$

So, the k-coordinate is (-6, 5)

3 0

3 years ago