If the work required to stretch a spring 2 ft beyond its natural length is 9 ft-lb,then the work that is needed to stretch it 18 inches beyond its natural length is 81 ft.lb.
Given that work required to stretch a spring 2 ft beyond its natural length is 9 ft-lb.
We are required to find the work that is needed to stretch 18 inches beyond its natural length.
Multiplication is basically finding out the product of two or more numbers.
Work required to stretch the spring 2 feet beyond its natural length=9 ft. lb.
So, to find the work that is required to stretch the spring 18 feet beyond its natural length, we have to multiply 9 with 9 which will give us 81. So the work required is 81 ft.lb.
Hence if the work required to stretch a spring 2 ft beyond its natural length is 9 ft-lb,then the work that is needed to stretch it 18 inches beyond its natural length is 81 ft.-lb.
Learn more about multiplication at brainly.com/question/10873737
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Where is the math problem?
Around $634.85 per year
Because:
$32.85+$35(12 months)+$3.5(52 weeks in a year)= Total cost per year
$420 $182
$32.85 + $420 + $182 = $634.85 per year
I think any irrational number would do this? I'm not positive though. Some examples may be pi or the square root of 2.
I think it’s gonna be 6 adults for every 42 students not really sure so sorry if I got it wrong
