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MrRissso [65]
3 years ago
12

Help with my homework please! Will give brainliest

Mathematics
1 answer:
Anna71 [15]3 years ago
6 0

Answer:

a) 72 cm^2

b) 9 cm^2

c) 9 cm^2

d) 60.39 cm^2

Step-by-step explanation:

a) the the length is 12 cm and the width is 6 cm. Area = lw

A=(12)(6)

A=72 cm^2

b) base equals 3 cm

Height equals 6 cm

A=1/2(3)(6)

A= 9 cm^2

c) base = 3 cm

height=6 cm

Area=1/2(3)(6)

A=9 cm^2

d) to to find the area of the parallelogram, You need to use Pythagorean theorem for one of the triangles.

3^2 + 6^2 = x^2

9 + 36 = x^2

45=x^2

✓45 = ✓x^2

x = 6.71 cm

12-3 = 9

now that you have all the sides for the parallelogram, multiply 6.71 times 9 to get the area.

A= 60.39 cm^2

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Answer:

y = 5x/2 + 2

Step-by-step explanation:

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3 years ago
The two objects are the same height, and the cylinder is just wide enough for the the box to fit inside with all 4 vertical edge
OLEGan [10]

Answer:

The answer is below

Step-by-step explanation:

The volume of a box with a length of l, width of w and a height of h is given by the formula:

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2 years ago
A large electronic office product contains 2000 electronic components. Assume that the probability that each component operates
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Answer:

The probability is 0.971032

Step-by-step explanation:

The variable that says the number of components that fail during the useful life of the product follows a binomial distribution.

The Binomial distribution apply when we have n identical and independent events with a probability p of success and a probability 1-p of not success. Then, the probability that x of the n events are success is given by:

P(x)=\frac{n!}{x!(n-x)!}*p^{x}*(1-p)^{n-x}

In this case, we have 2000 electronics components with a probability 0.005 of fail during the useful life of the product and a probability 0.995 that each component operates without failure during the useful life of the product. Then, the probability that x components of the 2000 fail is:

P(x)=\frac{2000!}{x!(2000-x)!}*0.005^{x}*(0.995)^{2000-x}     (eq. 1)

So, the probability that 5 or more of the original 2000 components fail during the useful life of the product is:

P(x ≥ 5) = P(5) + P(6) + ... + P(1999) + P(2000)

We can also calculated that as:

P(x ≥ 5) = 1 - P(x ≤ 4)

Where P(x ≤ 4) = P(0) + P(1) + P(2) + P(3) + P(4)

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Finally, P(x ≥ 5) is:

P(x ≥ 5) = 1 - 0.028968

P(x ≥ 5) = 0.971032

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3 years ago
I have no idea what this is since I was absent and my teacher is didn’t it explain it to me, someone?
MatroZZZ [7]

Answer:

Step-by-step explanation:

4 0
3 years ago
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