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makvit [3.9K]
3 years ago
14

Find the perimeter of shape ABCDE

Mathematics
1 answer:
EleoNora [17]3 years ago
6 0

Answer:

Perimeter of a triangle = 2*(length + breadth)

SO = 2*18+41

= 77 is the perimeter

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What is the answer to:
velikii [3]
Weird way to write it but alright! (Sideways) 

19pq^-2 x 5pq^6 = ?

These problems are pretty much single operations between each of the variables / constants. 

So it's like this: 

(19*5)(p*p)(q^-2*q^6) = ?

19*5 is 95.

For p*p remember that when two variables multiply there given powers add. In the case where the powers are not shown (like in the case of p*p) they are always assumed to be 1. So what is 1+1? 2. 

p*p is p^2

For q^-2*q^6 it is the same deal with the previous problem. So now the problem looks like this: 

-2 + 6 = 4 
(The two is negative, because the power is negative 2) 

So, q^4. 

Our final answer is all of the combined.... like a so: 

95p^2q^4
3 0
3 years ago
Let f be a function. Use each statement to find the coordinates of a point on the graph of f. f (5) = 9
omeli [17]

Answer:

400

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
The vertices of a triangle are p(3,7) Q(7,-6) R(-8,7). Name the vertices of the image reflected across the x axis
pantera1 [17]

Answer:

<em>P'(3,-7) Q'(7,6) R'(-8,-7).</em>

Step-by-step explanation:

<u>Reflection across the x-axis</u>

Given a point P(x,y), its reflection across the x-axis will map to point P'(x,-y), i.e., the y-coordinate gets inverted.

We are given the vertices of a triangle P(3,7) Q(7,-6) R(-8,7). The vertices of the image reflected across the x-axis are:

P'(3,-7) Q'(7,6) R'(-8,-7).

The new triangle has vertices P'Q'R'.

6 0
3 years ago
How do you do this question?
ElenaW [278]

x*y' + y = 8x

y' + y/x = 8 .... divide everything by x

dy/dx + y/x = 8

dy/dx + (1/x)*y = 8

We have something in the form

y' + P(x)*y = Q(x)

which is a first order ODE

The integrating factor is u(x) = e^{\int P(x)dx} = e^{\int (1/x) dx} = e^{\ln(x)} = x

Multiply both sides by the integrating factor (x) and we get the following:

dy/dx + (1/x)*y = 8

x*dy/dx + x*(1/x)*y = x*8

x*dy/dx + y = 8x

y + x*dy/dx = 8x

Note the left hand side is the result of using the product rule on xy. We technically didn't need the integrating factor since we already had the original equation in this format, but I wanted to use it anyway (since other ODE problems may not be as simple).

Since (xy)' turns into y + x*dy/dx, and vice versa, this means

y + x*dy/dx = 8x turns into (xy)' = 8x

Integrating both sides with respect to x leads to

xy = 4x^2 + C

y = (4x^2 + C)/x

y = (4x^2)/x + C/x

y = 4x + Cx^(-1)

where C is a constant. In this case, C = -5 leads to a solution

y = 4x - 5x^(-1)

you can check this answer by deriving both sides with respect to x

dy/dx = 4 + 5x^(-2)

Then plugging this along with y = 4x - 5x^(-1) into the ODE given, and you should find it satisfies that equation.

6 0
3 years ago
What is the measure of Zx?
alexgriva [62]

Answer:

66

Step-by-step explanation:

180 - 105 = 75

75 + 39 = 114

180 - 114 = 66

8 0
3 years ago
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