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zzz [600]
3 years ago
9

The pinata weighs 11/4 pounds without candy.He adds 8bags that weighs 3/8,3/8,1/2,1/2,1/2,3/4,3,11/4 how much will the pinata we

igh when it is filled with the eight bags of candy
Mathematics
1 answer:
Natalka [10]3 years ago
4 0

Answer:

Weight = \frac{23}{2}

Step-by-step explanation:

Given

Weight of Pinata = 11/4 lb

Weight of candies = 3/8, 3/8, 1/2 , 1/2, 1/2, 3/4, 3, 11/4

Required

Weight of Pinata when filled with candies

To solve this question, we simply need to add all weights together

First, we need to add up the weight of the candies

Candies =  \frac{3}{8} + \frac{3}{8} + \frac{1}{2}+ \frac{1}{2}+ \frac{1}{2}+ \frac{3}{4} + 3 + \frac{11}{4}

Take LCM

Candies = \frac{3 + 3 + 4 +4 + 4 + 6 + 24 + 22}{8}

Candies = \frac{70}{8}

Simplify:

Candies = \frac{35}{4}

Next; Add the weight of the candies to the weight of pinata

Weight = Candies + Pinata

Weight = \frac{35}{4} + \frac{11}{4}

Take LCM

Weight = \frac{35 + 11}{4}

Weight = \frac{46}{4}

Simplify

Weight = \frac{23}{2}

<em>Hence, the weight of the Pinata after it is filled with candies is 23/2 lb</em>

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