Question

The pinata weighs 11/4 pounds without candy.He adds 8bags that weighs 3/8,3/8,1/2,1/2,1/2,3/4,3,11/4 how much will the pinata weigh when it is filled with the eight bags of candy

Answer 1

Answer:

$Weight = \frac{23}{2}$

Step-by-step explanation:

Given

Weight of Pinata = 11/4 lb

Weight of candies = 3/8, 3/8, 1/2 , 1/2, 1/2, 3/4, 3, 11/4

Required

Weight of Pinata when filled with candies

To solve this question, we simply need to add all weights together

First, we need to add up the weight of the candies

$Candies = \frac{3}{8} + \frac{3}{8} + \frac{1}{2}+ \frac{1}{2}+ \frac{1}{2}+ \frac{3}{4} + 3 + \frac{11}{4}$

Take LCM

$Candies = \frac{3 + 3 + 4 +4 + 4 + 6 + 24 + 22}{8}$

$Candies = \frac{70}{8}$

Simplify:

$Candies = \frac{35}{4}$

Next; Add the weight of the candies to the weight of pinata

$Weight = Candies + Pinata$

$Weight = \frac{35}{4} + \frac{11}{4}$

Take LCM

$Weight = \frac{35 + 11}{4}$

$Weight = \frac{46}{4}$

Simplify

$Weight = \frac{23}{2}$

Hence, the weight of the Pinata after it is filled with candies is 23/2 lb