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Crazy boy [7]
3 years ago
15

At higher elevations water boils at lower temperatures. The temperature at which water boils is called the boiling point of wate

r. At sea level the boiling point of water is 100oC, while at 2 kilometers of elevation (about 6550 feet) the boiling point of water is 94oC. The function that gives the boiling point of water in oC, B
B
, at an elevation of x
x
kilometers is B(x)=100−3.5x
B(x)=100-3.5x
.

Determine the elevations at which the boiling point of water is between 84 oC and 96 oC. Give your answer accurate to 1 decimal place.
Mathematics
1 answer:
Leya [2.2K]3 years ago
7 0
B(x) = 100 - 3.5x
84 = 100 - 3.5x
3.5x = 100 - 84 = 16
x = 16/3.5 = 4.6 kilometers

96 = 100 - 3.5x
3.5x = 100 - 96 = 4
x = 4/3.5 = 1.1 kilometers

Therefore, the boiling point of water is between 84°C and 96°C at elevations of between 4.6 kilometers and 1.1 kilometers.
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Answer:

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Step-by-step explanation:

We have to calculate a 96% confidence interval for the proportion.

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p=X/n=640/800=0.8

The standard error of the proportion is:

\sigma_p=\sqrt{\dfrac{p(1-p)}{n}}=\sqrt{\dfrac{0.8*0.2}{800}}\\\\\\ \sigma_p=\sqrt{0.0002}=0.014

The critical z-value for a 96% confidence interval is z=2.054.

The margin of error (MOE) can be calculated as:

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Answer:

38.56

Step-by-step explanation:

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Can this be simplified?
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No Nothing Further Can Be Done
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20=v+9-16               Equation

20=(v)+(9+-16)        Combine \ like \ terms

20=v+-7

20=v-7            

v-7=20 

v-7+7=20+7     \ Add \ 7 \ to \ both \ sides

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