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Vera_Pavlovna [14]
3 years ago
12

Find the number of real number solutions for the equation. x^2+0x-1=0

Mathematics
1 answer:
Kazeer [188]3 years ago
3 0

Answer:

+1

-1

Step-by-step explanation:

Given equation :

x^{2} +0x-1 = 0

x^{2} -1 = 0\\x^{2} =1\\x=\sqrt{1}

x= ±1

x= 1 and x= -1

±1 lies in solution set of real numbers !

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Answer:

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