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2 years ago

Find the number of real number solutions for the equation. x^2+0x-1=0

Mathematics

1 answer:

Kazeer [188]2 years ago

3 0

Answer:

-1

Step-by-step explanation:

Given equation :

$x^{2} +0x-1$ = 0

$x^{2} -1 = 0\\x^{2} =1\\x=\sqrt{1}$

x= ±1

x= 1 and x= -1

±1 lies in solution set of real numbers !

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