Answer:
540
Step-by-step explanation:
(n-2)×180
(5-2)×180
3×180
540
Answer:
D. (1,0)
Step-by-step explanation:
Just plug in each coordinate for x and y into 4x+2y and see which one is less than or equal to 6.
Lets go through all of the possible answers:
<u>A</u>. (0,4)
4(0) + 2(4) ≤ 6
0 + 8 ≤ 6
8 ≤ 6
This is false. 8 is not less than or equal to 6.
<u>B</u>. (5,0)
4(5) + 2(0) ≤ 6
20 + 0 ≤ 6
20 ≤ 6
This is false. 20 is not less than or equal to 6.
<u>C</u>. (5,7)
4(5) + 2(7) ≤ 6
20 + 14 ≤ 6
34 ≤ 6
This is false because 35 is not less than or equal to 6
<u>D</u>. (1,0)
4(1) + 2(0) ≤ 6
4 + 0 ≤ 6
4 ≤ 6
This is true, because 4 is less than 6.
For indicies, the numerator is the normal power, and the denominator is a root as such. So 1/2 would be square root, 1/3 would be cube root, 1/4 would be 4th root and so on.
So, 64^(1/3) is the third root of 64, which is equal to 4.
<span>The name of the shape graphed by the function r ^ 2 = 9
cos (2 theta) is called the “<u>lemniscate</u>”. A lemniscate is a
plane curve with a feature shape which consists of two loops that meet at a
central point. The curve is also sometimes called as the lemniscate of
Bernoulli. </span>
Explanation:
The
period of coskθ is 2π/k. In this case, k = 2 therefore the
period is π.
r ^ 2 = 9 cos 2θ ≥0 → cos 2θ ≥0. So easily
one period can be chosen as θ ∈
[0, π] wherein cos 2θ ≥0.
As cos(2(−θ)) = cos2θ, the graph is symmetrical about the initial line.
Also,
as cos (2(pi-theta) = cos 2theta, the graph is symmetrical about the
vertical θ = π/2
A
Table for half period [0,π4/] is
adequate for the shape in Quarter1
Use symmetry for the other three quarters:
(r, θ) : (0,3)(3/√√2,π/8)(3√2/2,π/6)(0,π/4<span>)</span>
