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2 years ago

[10÷(7+3)]3 PLEASE HELP

Mathematics

1 answer:

makkiz [27]2 years ago

4 0

Answer:

Step-by-step explanation:

add perenthasis (10 \ 10) 3

(10\10) is 1

(1)3 = 3

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Which of the following uses the distributive property correctly?

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Answer:

The last one is correct: 3(x+5)=3 . X + 3 . 5

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3 years ago

The members of a cooking club are making cakes, which they will sell at a street fair for $8 apiece. It cost $30 for a booth at

Olin [163]

They need to sell 5 pieces to cover their expenditures (have a profit of zero).

<h3>How many cakes will they have sold?</h3>

We know that the costs are:

$30 for the booth at the fair.
$2 for each piece of cake they sell.

And the revenue is:

$8 for each piece of cake.

So, the profit (the difference between the revenue and the cost) for selling x pieces is:

p(x) = $8*x - $2*x - $30

p(x) = $6*x - $30

We want to find the value of x such that p(x) = 0, then:

0 = $6*x - $30

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They need to sell 5 pieces to cover their expenditures (have a profit of zero).

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2 years ago

a developer wants to develop 5 acres of land. Each lot in the develope is to be 1/12 of an acre. How many lots will the land dev

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2 years ago

Sandy drives in town at a rate of 25 miles per hour. It takes her 15 minutes to drive to the store. How far is it to the store?

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Answer: 6.25 miles

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3 years ago

Please help!!<br> Question is in the picture!!

Debora [2.8K]

$\frac{17}{60}$ and $\frac{1}{4}$ are the experimental probabilities from the table.

Solution:

Total number of times spun the spinner = 60

Number of times getting 1 = 12

Number of times getting 2 = 17

Number of times getting 3 = 15

Number of times getting 4 = 16

<u>Experimental probabilities from the table:</u>

Probability of getting 1 = $\frac{12}{60}=\frac{1}{5}$

Probability of getting 2 = $\frac{17}{60}$

Probability of getting 3 = $\frac{15}{60}=\frac{1}{4}$

Probability of getting 4 = $\frac{16}{60}=\frac{4}{15}$

<u>To determine which are the experimental probabilities from the table:</u>

Option A: 15

This is not obtained above. So, it is not the experimental probability.

Option B: $\frac{17}{60}$

This is obtained in the probability of getting 2.

So, it is the experimental probability.

Option C: $\frac{1}{4}$

This is obtained in the probability of getting 3.

So, it is the experimental probability.

Option D: $\frac{7}{15}$

This is not obtained above. So, it is not the experimental probability.

Option E: $\frac{12}{43}$

This is not obtained above. So, it is not the experimental probability.

Hence $\frac{17}{60}$ and $\frac{1}{4}$ are the experimental probabilities from the table.

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3 years ago