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algol13
3 years ago
8

[10÷(7+3)]3 PLEASE HELP

Mathematics
1 answer:
makkiz [27]3 years ago
4 0

Answer:

3

Step-by-step explanation:

add perenthasis (10 \ 10) 3

(10\10) is 1

(1)3 = 3

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In a survey of 100 students of Surkhet, 65 like to play football, 55 like
Katyanochek1 [597]

Answer:

15 students do not like either sport

Step-by-step explanation:

See the attached image.

Step 1: put 35 in the "like to play both" (intersection) area.

Step 2: subtract those 35 from the 65 football players.  65 - 35 = 30 players like football but not cricket.  Put 35 in the football but not cricket area.

Step 3: subtract 35 from the 55 cricket players.  55 - 35 = 20 players like cricket but not football.  Put 20 in the cricket but not football area.

Step 4: Add the 30 + 35 + 20 = 85 together.  So 85 players are accounted for as players of one or more sports.

Step 5: 100 - 85 = 15 must be the number of students who did not like either sport.  Put 15 in the area outside both circles.

6 0
3 years ago
The product of two positive numbers is 750. The first number is 5 less than the second number. The equation x(x – 5) = 750 can b
denpristay [2]

Answer:

  30

Step-by-step explanation:

You can try the answer choices to see what works.

  15·10 ≠ 750

  25·20 ≠ 750

  30·25 = 750 . . . . the larger number is 30

  50·45 ≠ 750

3 0
3 years ago
Read 2 more answers
What is 18 divided by 1/10 as a fraction
scoray [572]

Answer:

180

Step-by-step explanation:

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3 years ago
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Yael earns a straight commission as a real estate agent. Last month his total sales were $971,168.00. If Yael earns a 3% rate of
Nonamiya [84]
Yael’s gross income was $29,140
8 0
3 years ago
A sanitation supervisor is interested in testing to see if the mean amount of garbage per bin is different from 50. In a random
Harlamova29_29 [7]

Answer with explanation:

Given : Sample mean =\overline{x}=\text{48.47 pounds}

Standard deviation : \sigma=\text{ 3.1 pounds.}

Sample size : n = 36

Claim : \mu\neq50

∴ H_0:\mu=50

H_1:\mu\neq50

Since the alternative hypothesis is two tail , then the test is two tail test.

By using a z statistic and a 0.05 level of significance. Reject  H_0 if z < -1.960 or is z> 1.960.

Then , the test static for population mean is given by :-

z=\dfrac{\overline{x}-\mu}{\dfrac{\sigma}{\sqrt{n}}}

z=\dfrac{48.47-50}{\dfrac{3.1}{\sqrt{36}}}\approx-2.96

We reject H_0 since -2.96\leq -1.96. We have statistically significant evidence at \alpha=0.05 to show that the mean amount of garbage per bin is not different from 50.  

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3 years ago
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