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3 years ago

Explain the relationship between work and energy.

2 answers:

6 0

Energy is the ability to do work. Work done on an object gives the object potential or kinetic energy...

Ivanshal [37]3 years ago

3 0

$TME_{i}+W_{nc}=TME_{f}$
Total mechanical energy (initial) + work (non-conservative) = total mechanical energy (final) :)

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9 times 10 to the power of 7 is how many times as large as 3 times 10 to the power of 3

marysya [2.9K]

Answer:

30000

Step-by-step explanation:

9×10=90

90 power 7=90[10000000]

3×10=30

30 power 3=30[1000]

900000000÷30000=30000

7 0

3 years ago

What is the length of AC

Alex777 [14]

Answer:

Step-by-step explanation:

count A up to C

6 0

3 years ago

<img src="https://tex.z-dn.net/?f=%5Cboxed%7B%5Csf%202x%2B31%3D5%7D" id="TexFormula1" title="\boxed{\sf 2x+31=5}" alt="\boxed{\s

AleksAgata [21]

2x + 31 = 5

2x = 5 - 31

2x = -26

x = -26/2

x = -13.

_______

꧁✿ ᴿᴬᴵᴺᴮᴼᵂˢᴬᴸᵀ2222 ✬꧂

3 0

3 years ago

Read 2 more answers

PLEASE HELP!!! I am struggling

cestrela7 [59]

The ball will be at height 19 feet first at 0.7 sec and then at 1.42 sec.

Explanation:

We need to find the time at which the ball will be at height 19 feet.

Equation:

h = 3 + 34t - 16t²

19 = 3 + 34t - 16t²

16 = -16t² + 34t

-16t² + 34t - 16 = 0

On solving the equation, we get

t1 = 0.7 s and t2 = 1.42s

Therefore, the ball will be at height 19 feet first at 0.7 sec and then at 1.42 sec.

4 0

4 years ago

A contractor is required by a county planning department to submit one, two, three, four, or five forms (depending on the nature

Westkost [7]

Answer:

(a) The value of k is $\frac{1}{15}$ .

(b) The probability that at most three forms are required is 0.40.

(d) $P(y)=\frac{y^{2}}{50} ;\ y=1, 2, ...5$ is not the pmf of y.

Step-by-step explanation:

The random variable Y is defined as the number of forms required of the next applicant.

The probability mass function is defined as:

$P(y) = \left \{ {{ky};\ for \ y=1,2,...5 \atop {0};\ otherwise} \right$

(a)

The sum of all probabilities of an event is 1.

Use this law to compute the value of k.

$\sum P(y) = 1\\k+2k+3k+4k+5k=1\\15k=1\\k=\frac{1}{15}$

Thus, the value of k is $\frac{1}{15}$ .

(b)

Compute the value of P (Y ≤ 3) as follows:

$P(Y\leq 3)=P(Y=1)+P(Y=2)+P(Y=3)\\=\frac{1}{15}+\frac{2}{15}+ \frac{3}{15}\\=\frac{1+2+3}{15}\\ =\frac{6}{15} \\=0.40$

Thus, the probability that at most three forms are required is 0.40.

(c)

Compute the value of P (2 ≤ Y ≤ 4) as follows:

$P(2\leq Y\leq 4)=P(Y=2)+P(Y=3)+P(Y=4)\\=\frac{2}{15}+\frac{3}{15}+\frac{4}{15}\\ =\frac{2+3+4}{15}\\ =\frac{9}{15} \\=0.60$

Thus, the probability that between two and four forms (inclusive) are required is 0.60.

(d)

Now, for $P(y)=\frac{y^{2}}{50} ;\ y=1, 2, ...5$ to be the pmf of Y it has to satisfy the conditions:

$P(y)=\frac{y^{2}}{50}>0;\ for\ all\ values\ of\ y \\$
$\sum P(y)=1$

Check condition 1:

$y=1:\ P(y)=\frac{y^{2}}{50}=\frac{1}{50}=0.02>0\\y=2:\ P(y)=\frac{y^{2}}{50}=\frac{4}{50}=0.08>0 \\y=3:\ P(y)=\frac{y^{2}}{50}=\frac{9}{50}=0.18>0\\y=4:\ P(y)=\frac{y^{2}}{50}=\frac{16}{50}=0.32>0 \\y=5:\ P(y)=\frac{y^{2}}{50}=\frac{25}{50}=0.50>0$

Condition 1 is fulfilled.

Check condition 2:

$\sum P(y)=0.02+0.08+0.18+0.32+0.50=1.1>1$

Condition 2 is not satisfied.

Thus, $P(y)=\frac{y^{2}}{50} ;\ y=1, 2, ...5$ is not the pmf of y.

7 0

3 years ago