Answer:
Idk lol
Step-by-step explanation:
The probability of choosing a number that is not a multiple of 2 is P = 0.44
<h3 /><h3>How to find the probability?</h3>
We need to count the number of options for each digit.
- For the first digit, we have 8 options {1, 2, 3, 4, 5, 6, 7, 8}
- For the second digit, we have 9 options {0 ,1, 2, 3, 4, 5, 6, 7, 8}
- For the third digit, we have 9 options {0 ,1, 2, 3, 4, 5, 6, 7, 8}.
The total number of combinations is the product between the numbers of options:
C = 8*9*9 = 648
If we want our number to not be a multiple of 2 then it must end in a odd digit, the combinations that meet that condition are:
- For the first digit, we have 8 options {1, 2, 3, 4, 5, 6, 7, 8}
- For the second digit, we have 9 options {0 ,1, 2, 3, 4, 5, 6, 7, 8}
- For the third digit, we have 4 options {1, 3, 5, 7}.
C = 8*9*4 = 288
Then the probability of selecting a 3 digit number that is not a multiple of 2 is:
P = 288/648 = 0.44
If you want to learn more about probability, you can read:
brainly.com/question/251701
Answer:
(-3, -2) that is the answer please give me brainiest
Step-by-step explanation:
Answer:
The numbers are -16,-15 and -14
Step-by-step explanation:
Let
x ----> the first number
x+1 ----> the second number
x+2 ---> the third number
we know that
(1/4)x+(1/5)(x+1)=(1/7)(x+2)-5
Multiply by (4*5*7) both sides
35x+28(x+1)=20(x+2)-140*5
35x+28x+28=20x+40-700
43x=-688
x=-16
so
x+1=16+1=-15
x+2=-16+2=-14
The numbers are -16,-15 and -14
