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Alisiya [41]
3 years ago
15

Please solve these sumsfor 10 points​

Mathematics
2 answers:
il63 [147K]3 years ago
6 0

Answer:

hope its helpful for you

laila [671]3 years ago
3 0

Answer:

(i) = 3

(ii) = 20

Step-by-step explanation:

x = 1

y = -2

z = -1

(i) 4x - 3y + 7z

4(1) - 3(-2) + 7(-1)

4 + 6 - 7 = 3

(ii) 2x³ - 6y²z + 3xyz²

2(1)³ - 6(-2)²(-1) + 3(1)(-2)(-1)²

2 + 24 - 6 = 20

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6x - 4 = 16
Juli2301 [7.4K]

Hello!

Answer:

x=10/3

Step-by-step explanation:

First you want start by adding 4 to both sides

6x-4+4=16+4

6x=20

Then divide 6 to both sides,

6x/6=20/6

x= 10/3

Hope this helps! :)

4 0
2 years ago
90 POINTSSSSSSS:
denis23 [38]

Answer:

Part A:  12 plus x, the x being how much money he made on Sunday.

Part B: 2 plus x times 2

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
A tank with a capacity of 1600 L is full of a mixture of water and chlorine with a concentration of 0.0125 g of chlorine per lit
Veronika [31]

Answer:

y(t) = 20 [1600^(-5/3)] x (1600-24t)^ (5/3)

Step-by-step explanation:

1) Identify the problem

This is a differential equation problem

On this case the amount of liquid in the tank at time t is 1600−24t. (When the process begin, t=0 ) The reason of this is because the liquid is entering at 16 litres per second and leaving at 40 litres per second.

2) Define notation

y = amount of chlorine in the tank at time t,

Based on this definition, the concentration of chlorine at time t is y/(1600−24t) g/ L.

Since liquid is leaving the tank at 40L/s, the rate at which chlorine is leaving at time t is 40y/(1600−24t) (g/s).

For this we can find the differential equation

dy/dt = - (40 y)/ (1600 -24 t)

The equation above is a separable Differential equation. For this case the initial condition is y(0)=(1600L )(0.0125 gr/L) = 20 gr

3) Solve the differential equation

We can rewrite the differential equation like this:

dy/40y = -  (dt)/ (1600-24t)

And integrating on both sides we have:

(1/40) ln |y| = (1/24) ln (|1600-24t|) + C

Multiplying both sides by 40

ln |y| = (40/24) ln (|1600 -24t|) + C

And simplifying

ln |y| = (5/3) ln (|1600 -24t|) + C

Then exponentiating both sides:

e^ [ln |y|]= e^ [(5/3) ln (|1600-24t|) + C]

with e^c = C , we have this:

y(t) = C (1600-24t)^ (5/3)

4) Use the initial condition to find C

Since y(0) = 20 gr

20 = C (1600 -24x0)^ (5/3)

Solving for C we got

C = 20 / [1600^(5/3)] =  20 [1600^(-5/3)]

Finally the amount of chlorine in the tank as a function of time, would be given by this formula:

y(t) = 20 [1600^(-5/3)] x (1600-24t)^ (5/3)

7 0
3 years ago
For a quadratic function ƒ(x)=ax2+bx+c, ƒ(−1)<1, ƒ(1)>−1, and ƒ(3)<−4. What could be the sign of a?
denis23 [38]

Answer:

"a" must be negative

Step-by-step explanation:

The slope between points (-1, 1) and (1, -1) is a minimum of (-1-1)/(1-(-1)) = -1.

The slope between points (1, -1 and (3, -4) is a maximum of (-4-(-1))/(3-1) = -3/2.

Thus, as x increases, the slope is decreasing. In order for that to be the case, the value of <em>a</em> must satisfy a < 0.

4 0
3 years ago
Find the distance between the pair of points.
SVEN [57.7K]

Answer:

Distance is \sqrt{290} units

Step-by-step explanation:

Use the distance formula which is d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} where d is the distance between points (x_1,y_1) and (x_2,y_2)

We are given that (x_1,y_1) is (-6,-23) and (x_2,y_2) is (-23,-24), therefore the distance between the two points is:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

d=\sqrt{(-23-(-6))^2+(-24-(-23))^2}

d=\sqrt{(-23+6))^2+(-24+23))^2}

d=\sqrt{(-17)^2+(-1)^2}

d=\sqrt{289+1}

d=\sqrt{290}

Therefore, the distance between (-6,-23) and (-23,-24) is \sqrt{290} units.

3 0
2 years ago
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