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Nikolay [14]
3 years ago
12

The number of vertices a triangle has 3 6 4 5

Mathematics
1 answer:
sergij07 [2.7K]3 years ago
4 0
<h2>the answer is - 3.........</h2>
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What is the equation of a line with a slope of ​3​ and a point
seraphim [82]
Answer: y = 3x-8

------------------------------------------------
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Explanation:

The slope is 3, so m = 3

The given point is (3,1) meaning x = 3 and y = 1. The x coordinate is always listed first in an ordered pair. The general format is (x,y)

We'll use m = 3, x = 3 and y = 1 to find the y intercept

y = mx+b
y = m*x+b
1 = 3*3+b ... plug in m = 3, x = 3 and y = 1
1 = 9+b
1-9 = 9+b-9 ... subtract 9 from both sides
-8 = b
b = -8

----------------

So we're given m = 3 as the slope and we just found that b = -8 is the y intercept

So y = mx+b updates to y = 3x-8. This is the final answer.

----------------

Side Notes:
* The slope of 3 means rise/run = 3/1 indicating each time we go up 3, we move to the right 1
* The y intercept -8 is the location on the vertical y axis numberline where the graph crosses. The point (0,-8) is on this line.

8 0
3 years ago
Which equation can be used to find the surface area of the cylinder?
ki77a [65]

Step-by-step explanation:

Surface Area of the Cylinder

= 2πr² + 2πrh

r = 4 in

h = 16 in

Surface Area :

= 2πr² + 2πrh

= 2π (4)² + 2π (4) (16)

<em>Hope </em><em>it </em><em>helpful </em><em>and </em><em>useful </em><em>:</em><em>)</em>

6 0
3 years ago
What is the general form of the equation for the given circle?
Westkost [7]
I think the answer is B or C
7 0
3 years ago
If m -(-3) &gt; 17, which is a possible value for m?
masha68 [24]

Step-by-step explanation:

m-(-3)>17

m +3>17

m >17-3

m>14

5 0
3 years ago
1 pt) find the average rate of change of the function over the given intervals. h(t)=\cot (t);
blondinia [14]

\text{Consider the function}\\&#10;\\&#10;h(t)=\cot(t) \text{ on the interval }\left [ \frac{\pi}{4}, \ \frac{3\pi}{4} \right ]\\&#10;\\&#10;\text{we know that the average rate of change of a funtion f(x) over the }\\&#10;\text{interval [a, b] is given by}\\&#10;\\&#10;f_{avg}=\frac{f(b)-f(a)}{b-a}\\&#10;\\&#10;\text{so using this, the average rate of change of the given function is}

h_{avg}=\frac{h\left ( \frac{3\pi}{4} \right )-h\left ( \frac{\pi}{4} \right )}{\frac{3\pi}{4}-\frac{\pi}{4}}\\&#10;\\&#10;=\frac{\cot \left ( \frac{3\pi}{4} \right )-\cot \left ( \frac{\pi}{4} \right )}{\frac{3\pi-\pi}{4}}\\&#10;\\&#10;=\frac{(-1)-(1)}{\frac{2\pi}{4}}\\&#10;\\&#10;=\frac{-2}{\frac{\pi}{2}}\\&#10;\\&#10;\text{Average rate of change of function}=\frac{-4}{\pi}

6 0
3 years ago
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