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Law Incorporation [45]
4 years ago
12

BRAINLIESTTTTTT ASAP!!!!! In a survey among 1825 randomly selected high school students 466 said they were current smokers.

Mathematics
1 answer:
NARA [144]4 years ago
5 0
24 24 24 24 24 safegsthrdyjtfukyyfsshgfdsasdfghjkkjhg
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What decimal is equal to 6/25
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6/25 is equal to 0.24 in decimal form
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An artist is painting a parallelogram with a base of 45 cm and a height of 34 cm. One tube of paint will cover 400 cm2. How many
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                        Hope this Helped! ~Giz
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3. Princess can sell an average of 12 muffins per day. She needs to earn $9 per day to meet her fundraising goal.
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5 0
3 years ago
A zoologist is studying four very closely related feline species. She wishes to compare their gestation periods. An observationa
diamong [38]

Answer:

p_v= 0.01

Since the significance level is 0.05 we see that pv so we have enough evidence to reject the null hypothesis. And the best conclusion for this case would be:

b. at least some, but not all, of the gestation periods across all four species are the same

Because is only to identify if AT LEAST one mean is different, NOT to conclude that the all the means are different.

Step-by-step explanation:

Previous concepts

Analysis of variance (ANOVA) "is used to analyze the differences among group means in a sample".  

The sum of squares "is the sum of the square of variation, where variation is defined as the spread between each individual value and the grand mean"  

Solution to the problem

The hypothesis for this case are:

Null hypothesis: \mu_{A}=\mu_{B}=\mu_{C}= \mu_D

Alternative hypothesis: Not all the means are equal \mu_{i}\neq \mu_{j}, i,j=A,B,C,D

In order to find the mean square between treatments (MSTR), we need to find first the sum of squares and the degrees of freedom.

If we assume that we have p=4 groups and on each group from j=1,\dots,p we have n_j individuals on each group we can define the following formulas of variation:  

SS_{total}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x)^2  

SS_{between}=SS_{model}=\sum_{j=1}^p n_j (\bar x_{j}-\bar x)^2  

SS_{within}=SS_{error}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x_j)^2  

And we have this property  

SST=SS_{between}+SS_{within}  

And in order to test this hypothesis we need to ue an F statistic and for this case the p value calculated is

p_v= 0.01

Since the significance level is 0.05 we see that pv so we have enough evidence to reject the null hypothesis. And the best conclusion for this case would be:

b. at least some, but not all, of the gestation periods across all four species are the same

Because is only to identify if AT LEAST one mean is different NOT to conclude that the all the means are different.

8 0
4 years ago
Find the slope of each line.<br><br>A) -3/4<br><br>B) 3/4<br><br>C) 4/3<br><br>D) -4/3​
uysha [10]

-3/4

To calculate slope, use the formula

Slope (m) = y2 - y1/x2 - x1

Then choose two points on the line of the graph (as shown in attached file)

Input the values as read from the graph and solve for slope using the graph

Note that the discrepancy in answer is due to the assumption made, no value was given on the graph.

3 0
3 years ago
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